Question

我想在越狱iPhone的主屏幕上模拟点击应用图标。我使用下面的代码，但它无法生效。我做错了吗？

getFrontMostAppPort()的方法是否正确？事件，如果我尝试使用GSSendSystemEvent()，它没有任何效果。

顺便说一句，我的意思是越狱装置。谁能给我一个帮助？我非常感激。

// Framework Paths
#define SBSERVPATH  "/System/Library/PrivateFrameworks/SpringBoardServices.framework/SpringBoardServices"

static mach_port_t getFrontMostAppPort() {
    bool locked;
    bool passcode;
    mach_port_t *port;
    void *lib = dlopen(SBSERVPATH, RTLD_LAZY);
    int (*SBSSpringBoardServerPort)() = dlsym(lib, "SBSSpringBoardServerPort");
    void* (*SBGetScreenLockStatus)(mach_port_t* port, bool *lockStatus, bool *passcodeEnabled) = dlsym(lib, "SBGetScreenLockStatus");
    port = (mach_port_t *)SBSSpringBoardServerPort();
    dlclose(lib);
    SBGetScreenLockStatus(port, &locked, &passcode);
    void *(*SBFrontmostApplicationDisplayIdentifier)(mach_port_t *port, char *result) = dlsym(lib, "SBFrontmostApplicationDisplayIdentifier");
    char appId[256];
    memset(appId, 0, sizeof(appId));
    SBFrontmostApplicationDisplayIdentifier(port, appId);
    NSString * frontmostApp=[NSString stringWithFormat:@"%s",appId];
    if([frontmostApp length] == 0 || locked)
        return GSGetPurpleSystemEventPort();
    else
        return GSCopyPurpleNamedPort(appId);
}

static void sendTouchEvent(GSHandInfoType handInfoType, CGPoint point) {

    uint8_t touchEvent[sizeof(GSEventRecord) + sizeof(GSHandInfo) + sizeof(GSPathInfo)];

    // structure of touch GSEvent
    struct GSTouchEvent {
        GSEventRecord record;
        GSHandInfo    handInfo;
    } * event = (struct GSTouchEvent*) &touchEvent;
    bzero(touchEvent, sizeof(touchEvent));

    // set up GSEvent
    event->record.type = kGSEventHand;
    event->record.subtype = kGSEventSubTypeUnknown;
    event->record.windowLocation = point;
    event->record.timestamp = GSCurrentEventTimestamp();
    event->record.infoSize = sizeof(GSHandInfo) + sizeof(GSPathInfo);
    event->handInfo.type = handInfoType;
    event->handInfo.x52 = 1;

    bzero(&event->handInfo.pathInfos[0], sizeof(GSPathInfo));
    event->handInfo.pathInfos[0].pathIndex     = 1;
    event->handInfo.pathInfos[0].pathIdentity  = 2;
    event->handInfo.pathInfos[0].pathProximity = (handInfoType == kGSHandInfoTypeTouchDown || handInfoType == kGSHandInfoTypeTouchDragged || handInfoType == kGSHandInfoTypeTouchMoved) ? 0x03 : 0x00;;
    event->handInfo.pathInfos[0].pathLocation  = point;


    mach_port_t port = (mach_port_t)getFrontMostAppPort();
    GSSendEvent((GSEventRecord *)event, port);
}

// why nothing happened?
static clickOnHome() {
    sendTouchEvent(kGSHandInfoTypeTouchDown, CGPointMake(100, 200));
    sleep(1);
    sendTouchEvent(kGSHandInfoTypeTouchUp, CGPointMake(100, 200));
}

Answer 1

是的，我认为您的getFrontMostAppPort()方法很好，if you got it from here。

我想了解你想要的东西：

如果您只是想打开一个特定的应用程序（通过bundleId），那么我建议使用Cydia上提供的命令行open实用程序。您可以使用system()或exec电话以编程方式拨打此电话。或者，如果您想在自己的应用中构建这种“开放”功能，see my answer here。
现在，也许您正在编写应用程序的代码或调整后台的代码，而不是前景 app 。并且，也许您确实需要触摸特定的{x，y} 坐标，而不是通过其bundleId打开应用程序。如果你真的想要，那么这段代码适合我（based on this answer ... with corrections）：

static void sendTouchEvent(GSHandInfoType handInfoType, CGPoint point) {

   uint8_t gsTouchEvent[sizeof(GSEventRecord) + sizeof(GSHandInfo) + sizeof(GSPathInfo)];

   // structure of touch GSEvent
   struct GSTouchEvent {
      GSEventRecord record;
      GSHandInfo    handInfo;
   } * touchEvent = (struct GSTouchEvent*) &gsTouchEvent;
   bzero(touchEvent, sizeof(touchEvent));

   touchEvent->record.type = kGSEventHand;
   touchEvent->record.subtype = kGSEventSubTypeUnknown;
   touchEvent->record.location = point;
   touchEvent->record.windowLocation = point;
   touchEvent->record.infoSize = sizeof(GSHandInfo) + sizeof(GSPathInfo);
   touchEvent->record.timestamp = GSCurrentEventTimestamp();
   //touchEvent->record.window = winRef;
   //touchEvent->record.senderPID = 919;  
   bzero(&touchEvent->handInfo, sizeof(GSHandInfo));
   bzero(&touchEvent->handInfo.pathInfos[0], sizeof(GSPathInfo));
   GSHandInfo touchEventHandInfo;
   touchEventHandInfo._0x5C = 0;
   touchEventHandInfo.deltaX = 0;
   touchEventHandInfo.deltaY = 0;
   touchEventHandInfo.height = 0;
   touchEventHandInfo.width = 0;
   touchEvent->handInfo = touchEventHandInfo;
   touchEvent->handInfo.type = (handInfoType == kGSHandInfoTypeTouchDown) ? 2 : 1;
   touchEvent->handInfo.deltaX = 1;
   touchEvent->handInfo.deltaY = 1;
   touchEvent->handInfo.pathInfosCount = 0;
   touchEvent->handInfo.pathInfos[0].pathIndex = 1;
   touchEvent->handInfo.pathInfos[0].pathIdentity = 2;
   touchEvent->handInfo.pathInfos[0].pathProximity = (handInfoType == kGSHandInfoTypeTouchDown || handInfoType == kGSHandInfoTypeTouchDragged || handInfoType == kGSHandInfoTypeTouchMoved) ? 0x03: 0x00;
   touchEvent->handInfo.x52 = 1;  // iOS 5+, I believe
   touchEvent->handInfo.pathInfos[0].pathLocation = point;
   //touchEvent->handInfo.pathInfos[0].pathWindow = winRef;

   GSEventRecord* record = (GSEventRecord*) touchEvent;
   record->timestamp = GSCurrentEventTimestamp();

   GSSendEvent(record, getFrontMostAppPort());
}

- (void) simulateHomeScreenTouch {
   CGPoint location = CGPointMake(50, 50);
   sendTouchEvent(kGSHandInfoTypeTouchDown, location);

   double delayInSeconds = 0.1;
   dispatch_time_t popTime = dispatch_time(DISPATCH_TIME_NOW, (int64_t)(delayInSeconds * NSEC_PER_SEC));
   dispatch_after(popTime, dispatch_get_main_queue(), ^(void){
      sendTouchEvent(kGSHandInfoTypeTouchUp, location);
   });
}

只要SpringBoard是最前面的应用程序（没有其他应用程序打开），这将向SpringBoard发送一个触摸/向上事件对。此外，您还可以查看handInfoType值映射到2或1的位置，以了解触摸和向上事件。上面的代码假定这些是您正在生成的两种类型的事件。

注意：我首先尝试使用坐标x = 100，y = 200，但没有任何反应。我认为坐标两个主屏幕图标。使用其他坐标（例如x = 50，y = 50）可以正常工作。

注意II ：我不相信这个解决方案实际上需要越狱。它使用私有API ，因此无法提交到App Store，但这适用于企业中的被盗手机或业余爱好者部署。

如何模拟（越狱）iPhone主屏幕上的点击？

1 个答案: