编辑:我为此创建了一个ticket,其中有关于这种做法的替代方案的数据。
我有updated the code尝试使用MY_CXT的回调,因为gcxt没有跨线程存储。然而,这段错误在ENTER。
#include "EXTERN.h"
#include "perl.h"
#include "XSUB.h"
#ifndef aTHX_
#define aTHX_
#endif
#ifdef USE_THREADS
#define HAVE_TLS_CONTEXT
#endif
/* For windows */
#ifndef SDL_PERL_DEFINES_H
#define SDL_PERL_DEFINES_H
#ifdef HAVE_TLS_CONTEXT
PerlInterpreter *parent_perl = NULL;
extern PerlInterpreter *parent_perl;
#define GET_TLS_CONTEXT parent_perl = PERL_GET_CONTEXT;
#define ENTER_TLS_CONTEXT \
PerlInterpreter *current_perl = PERL_GET_CONTEXT; \
PERL_SET_CONTEXT(parent_perl); { \
PerlInterpreter *my_perl = parent_perl;
#define LEAVE_TLS_CONTEXT \
} PERL_SET_CONTEXT(current_perl);
#else
#define GET_TLS_CONTEXT /* TLS context not enabled */
#define ENTER_TLS_CONTEXT /* TLS context not enabled */
#define LEAVE_TLS_CONTEXT /* TLS context not enabled */
#endif
#endif
#include <SDL.h>
#define MY_CXT_KEY "SDL::Time::_guts" XS_VERSION
typedef struct {
void* data;
SV* callback;
Uint32 retval;
} my_cxt_t;
static my_cxt_t gcxt;
START_MY_CXT
static Uint32 add_timer_cb ( Uint32 interval, void* param )
{
ENTER_TLS_CONTEXT
dMY_CXT;
dSP;
int back;
ENTER; //SEGFAULTS RIGHT HERE!
SAVETMPS;
PUSHMARK(SP);
XPUSHs(sv_2mortal(newSViv(interval)));
PUTBACK;
if (0 != (back = call_sv(MY_CXT.callback,G_SCALAR))) {
SPAGAIN;
if (back != 1 ) Perl_croak (aTHX_ "Timer Callback failed!");
MY_CXT.retval = POPi;
} else {
Perl_croak(aTHX_ "Timer Callback failed!");
}
FREETMPS;
LEAVE;
LEAVE_TLS_CONTEXT
dMY_CXT;
return MY_CXT.retval;
}
MODULE = SDL::Time PACKAGE = SDL::Time PREFIX = time_
BOOT:
{
MY_CXT_INIT;
}
SDL_TimerID
time_add_timer ( interval, cmd )
Uint32 interval
void *cmd
PREINIT:
dMY_CXT;
CODE:
MY_CXT.callback=cmd;
gcxt = MY_CXT;
RETVAL = SDL_AddTimer(interval,add_timer_cb,(void *)cmd);
OUTPUT:
RETVAL
void
CLONE(...)
CODE:
MY_CXT_CLONE;
我一进入ENTER进行回调就会出现这个段错误。
use SDL;
use SDL::Time;
SDL::init(SDL_INIT_TIMER);
my $time = 0;
SDL::Timer::add_timer(100, sub { $time++; return $_[0]} );
sleep(10);
print "Never Prints";
输出
$
应该是
$ Never Prints
答案 0 :(得分:4)
快速评论:
答案 1 :(得分:0)
$ time需要是一个共享变量 - 否则perl可以使用变量的单独副本。
答案 2 :(得分:0)
我首选的处理方法是将数据存储在PL_modglobal哈希中。它会自动绑定到当前的解释器。
答案 3 :(得分:-1)