我尝试将函数的操作次数减少到只有一个查询，但现在我无法检索任何结果：
function retrive_avaible_operator($Hostname, $Username, $Password, $DatabaseName, $SupportUserPerDepaTable, $SupportUserTable,$dep){
$query = "SELECT b.id
FROM ".$SupportUserTable." b
INNER JOIN ".$SupportUserPerDepaTable." a
ON b.id=a.user_id
WHERE a.department_id=? AND b.holiday='0' AND a.user_id!=".$_SESSION['id']."
ORDER BY b.assigned_tickets ASC LIMIT 1";
$mysqli = new mysqli($Hostname, $Username, $Password, $DatabaseName);
$stmt = $mysqli->stmt_init();
$prepared = $stmt->prepare($query);
if($prepared){
if($stmt->bind_param('i', $dep)){
if($stmt->execute()){
$stmt->store_result();
$result = $stmt->bind_result($camaro);
if($stmt->num_rows>0){
while (mysqli_stmt_fetch($stmt))
$selopid=$camaro;
return $selopid;
}
else
return 'No Operator Available';
}
else
return mysqli_stmt_error($stmt);
}
else
return mysqli_stmt_error($stmt);
}
else
return mysqli_stmt_error($stmt);
}
在此之前尝试操作（这是两个不同的查询）：
$SupportUserPerDepaTable a.department_id=? $SupportUserTable中选择所有ID，其中id位于之前的结果中，holiday='0' 虽然有效，但现在只返回No Operator Available
这些是表格：
CREATE TABLE IF NOT EXISTS `razorphyn_support_user_departments` (
`id` BIGINT(11) UNSIGNED NOT NULL AUTO_INCREMENT,
`department_id` BIGINT(11) UNSIGNED NOT NULL,
`department_name` VARCHAR(70) NOT NULL,
`user_id` BIGINT(11) UNSIGNED NOT NULL,
`holiday` ENUM('0','1') NOT NULL DEFAULT '0',
PRIMARY KEY (`id`),
UNIQUE KEY(`department_name`,`user_id`),
INDEX(`department_id`,`department_name`,`user_id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=0;
和
CREATE TABLE IF NOT EXISTS `razorphyn_support_users` (
`id` BIGINT(15) UNSIGNED NOT NULL AUTO_INCREMENT,
`name` VARCHAR(50) NOT NULL,
`mail` VARCHAR(50) NOT NULL,
`password` VARCHAR(200) NOT NULL,
`reg_key` VARCHAR(260) ,
`tmp_password` VARCHAR(87) ,
`ip_address` VARCHAR(50) NOT NULL,
`status` ENUM('0','1','2','3','4') NOT NULL DEFAULT '3',
`holiday` ENUM('0','1') NOT NULL DEFAULT '0',
`mail_alert` ENUM('no','yes') NOT NULL DEFAULT 'yes',
`assigned_tickets` INT(5) UNSIGNED NOT NULL DEFAULT 0,
`solved_tickets` BIGINT(11) UNSIGNED NOT NULL DEFAULT 0,
`number_rating` BIGINT(6) UNSIGNED NOT NULL DEFAULT 0,
`rating` DECIMAL(4,2) UNSIGNED NOT NULL DEFAULT 0,
PRIMARY KEY (`id`),
UNIQUE KEY(`mail`),
INDEX (`name`,`mail`,`status`,`holiday`,`assigned_tickets`,`solved_tickets`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=55;
修改
我发现（不幸的是，因为前面的代码非常丑陋和混乱）（我删除了所有控件，但是它有效）：
function retrive_avaible_operator($Hostname, $Username, $Password, $DatabaseName, $SupportUserPerDepaTable, $SupportUserTable,$dep){
$query = "SELECT `user_id` FROM ".$SupportUserPerDepaTable." WHERE `department_id`=? AND `user_id`!=".$_SESSION['id'] ;
$mysqli = new mysqli($Hostname, $Username, $Password, $DatabaseName);
$stmt = $mysqli->stmt_init();
$prepared = $stmt->prepare($query);
$stmt->bind_param('i', $dep)
$stmt->execute()
$stmt->store_result();
$operator=array();
$result = $stmt->bind_result($camaro);
if($stmt->num_rows>0){
while (mysqli_stmt_fetch($stmt))
$operator[]=$camaro;
$operator=join(',',$operator);
$query = "SELECT `id` FROM ".$SupportUserTable." WHERE `id` IN (".$operator.") AND `holiday`='0' ORDER BY `assigned_tickets` ASC LIMIT 1" ;
$prepared = $stmt->prepare($query);
$prepared)
$stmt->execute()
$stmt->store_result();
$result = $stmt->bind_result($camaro);
if($stmt->num_rows>0){
while (mysqli_stmt_fetch($stmt))
$selopid=$camaro;
return $selopid;
}
else{
$query = "SELECT `id` FROM ".$SupportUserTable." WHERE `status`=2 AND `holiday`=0 AND `id`!=".$_SESSION['id']." ORDER BY `assigned_tickets` ASC, `solved_tickets` ASC LIMIT 1" ;
$prepared = $stmt->prepare($query);
$prepared
$stmt->execute()
$stmt->store_result();
$result = $stmt->bind_result($camaro);
if($stmt->num_rows>0){
while (mysqli_stmt_fetch($stmt))
$selopid=$camaro;
return $selopid;
}
else
return 'No Operator Available';
}
}
else{
$query = "SELECT `id` FROM ".$SupportUserTable." WHERE `status`='2' AND `holiday`='0' AND `id`!=".$_SESSION['id']." ORDER BY `assigned_tickets` ASC, `solved_tickets` ASC LIMIT 1" ;
$prepared = $stmt->prepare($query);
$stmt->execute()
$stmt->store_result();
$result = $stmt->bind_result($camaro);
if($stmt->num_rows>0){
while (mysqli_stmt_fetch($stmt))
$selopid=$camaro;
return $selopid;
}
else
return 'No Operator Available';
}
$mysqli->close();
}
答案 0 :(得分：0)
你应该能够大大缩小这一点。在开始时，您只是查询$SupportUserPerDepaTable获取user_id，只是将它们加入到第二个查询的逗号分隔字符串中。您应该能够通过将其转换为子查询来消除此问题。第3和第4个查询是多余的，是前一个if / else情况的产物，因此您可以将这些查询组合起来，因为我们已经消除了top if条件。使用底部的“丑陋”代码，我将其浓缩为：
$mysqli = new mysqli($Hostname, $Username, $Password, $DatabaseName);
$stmt = $mysqli->stmt_init();
$query = "
SELECT `id`
FROM ".$SupportUserTable."
WHERE `id` IN (
SELECT `user_id`
FROM ".$SupportUserPerDepaTable."
WHERE `department_id`= ?
AND `user_id`!=".$_SESSION['id']."
)
AND `holiday`='0'
ORDER BY `assigned_tickets` ASC
LIMIT 1" ;
$prepared = $stmt->prepare($query);
$stmt->bind_param('i', $dep);
$stmt->execute();
$stmt->store_result();
$operator=array();
$result = $stmt->bind_result($camaro);
if($stmt->num_rows>0){
while (mysqli_stmt_fetch($stmt))
$selopid=$camaro;
return $selopid;
}
else{
$query = "
SELECT `id`
FROM ".$SupportUserTable."
WHERE `status`= 2
AND `holiday`=0
AND `id`!=".$_SESSION['id']."
ORDER BY `assigned_tickets` ASC
,`solved_tickets` ASC
LIMIT 1" ;
$prepared = $stmt->prepare($query);
$stmt->execute();
$stmt->store_result();
$result = $stmt->bind_result($camaro);
if($stmt->num_rows>0){
while (mysqli_stmt_fetch($stmt))
$selopid=$camaro;
return $selopid;
}
else{
return 'No Operator Available';
}
}
$mysqli->close();
您可以通过使用组合限制为1的UNION进一步将2个查询压缩为1：
(
SELECT `id`
FROM ".$SupportUserTable."
WHERE `id` IN (
SELECT `user_id`
FROM ".$SupportUserPerDepaTable."
WHERE `department_id`= ?
AND `user_id`!=".$_SESSION['id']."
)
AND `holiday`='0'
ORDER BY `assigned_tickets` ASC
UNION
SELECT `id`
FROM ".$SupportUserTable."
WHERE `status`= 2
AND `holiday`=0
AND `id`!=".$_SESSION['id']."
ORDER BY `assigned_tickets` ASC
,`solved_tickets` ASC
)
LIMIT 1;
或可能使用OR条件，具体取决于dept表中员工的状态代码，如：
SELECT `id`
FROM ".$SupportUserTable."
WHERE `holiday`='0'
AND (
`id` IN (
SELECT `user_id`
FROM ".$SupportUserPerDepaTable."
WHERE `department_id`= ?
AND `user_id`!=".$_SESSION['id']."
)
AND `status`= ('some code other than 2?')
)
OR (
`status`= 2
AND `id`! = ".$_SESSION['id']."
)
ORDER BY status (asc or desc?)
,`assigned_tickets` ASC
,`solved_tickets` ASC
LIMIT 1;
我没有对此进行测试，因为这需要花费太多时间来设置数据库表，输入样本数据并全部测试，所以如果有任何小错误，请原谅我，但这应该指向正确的方向。如果这不起作用并且您想要将一些示例数据发布到http://sqlfiddle.com/并提供一些预期输出的示例，我将重试一些查询以查看我能做什么。