Question

我需要生成这个简单的XML，寻找一种简洁的方法来生成它。

<order>
<user>2343></user>
<creditcardtype>2333></creditcarttype>
<country>USA</country>
<orderDetails>
   <amount>23434</amount>
   <shipping>32</shipping>
</orderDetails>
</order>

Answer 1

使用XDocument类，所以代码就像

XDocument srcTree = new XDocument(
    new XElement("order",
        new XElement("user", "2343"),
        new XElement("creditcardtype", "2333"),
        new XElement("country", "USA"),
        new XElement("orderDetails",
            new XElement ("amount", "23434"),
            new XElement ("shipping", "32")

        )
    )
);

Answer 2

自XDocument采取后，这是一个XmlWriter答案：

    StringWriter sw = new StringWriter();
    using (XmlWriter xw = XmlWriter.Create(sw)) {
        xw.WriteStartElement("order");
        xw.WriteElementString("user", "2343");
        xw.WriteElementString("creditcardtype", "2333");
        xw.WriteElementString("country", "USA");
        xw.WriteStartElement("orderDetails");
        xw.WriteElementString("amount", "23434");
        xw.WriteElementString("shipping", "32");
        xw.WriteEndElement();
        xw.WriteEndElement();
    }
    string s = sw.ToString();

或XmlSerializer：

[XmlRoot("order")] public class Order {
    [XmlElement("user")] public int User { get; set; }
    [XmlElement("creditcardtype")] public int CreditCardType { get; set; }
    [XmlElement("country")] public string Country { get; set; }
    [XmlElement("orderDetails")] public OrderDetails Details { get; set; }
}
public class OrderDetails {
    [XmlElement("amount")] public int Amount { get; set; }
    [XmlElement("shipping")] public int Shipping { get; set; }
}
....
var order = new Order {
    User = 2343, CreditCardType = 2333, Country = "USA",
    Details = new OrderDetails {
        Amount = 23434,
        Shipping = 32
    }
};
XmlSerializer ser = new XmlSerializer(order.GetType());
StringWriter sw = new StringWriter();
ser.Serialize(sw, order);
string s = sw.ToString();

Answer 3

请参阅LINQ to XMl方法来做到这一点，就像这样

XDocument doc = new XDocument(new XElement("order",
                   new XElement("user", "2343"),
                   new XElement("creditcardtype", "2333"),
                   new XElement("country", "USA"),
               new XElement("orderDetails",
                   new XElement("amount", "23434"),
                   new XElement("shipping", "32"))));
doc.Save("myxml.xml");

Answer 4

XmlDocument xml = new XmlDocument();

XmlElement order = xml.CreateElement("order");

xml.AppendChild(order);

XmlElement user = xml.CreateElement("user");
user.InnerText = "2343";
order.AppendChild(user);

XmlElement ccType = xml.CreateElement("creditcardtype");
ccType.InnerText = "2333";
order.AppendChild(ccType);

等

Answer 5

编写描述结构的XML模式。（您还可以使用xsd.exe根据给定的XML文件自动生成架构。）
使用xsd.exe /classes根据您的XML架构生成C＃类。
现在，您可以使用XmlSerializer类从/向C＃对象结构序列化/反序列化XML。

还有codeproject article描述了这种方法。

Answer 6

我会使用Linq to XML建议，但为了完整起见，我只需要添加这个：

var xe = XElement.Parse("<order><user>2343</user><creditcardtype>2333</creditcarttype><country>USA</country><orderDetails><amount>23434</amount><shipping>32</shipping></orderDetails></order>");

：）

你将如何在c＃中构建这个xml

6 个答案: