Question

我已将字符串声明为属性 MasterViewController.h

    @property (nonatomic , readwrite) NSString *theString;

这是我的prepareForSegue方法

     - (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
      if ([[segue identifier] isEqualToString:@"showDetail"]) {

    NSIndexPath *indexPath = [self.tableView indexPathForSelectedRow];
    NSString *string = [feeds[indexPath.row] objectForKey: @"link"];
   [[segue destinationViewController] setTheString:string];

  //UITextField *dest = [segue destinationViewController];
  //dest.theString = string;
}

}

DetailViewController.h 我已经为textView

创建了一个插座

    @interface APPDetailViewController : UIViewController
    @property (weak, nonatomic) IBOutlet UITextView *textView;

现在，在实现中代码是什么，所以我可以在MasterViewController中将“theString”显示到DetailViewController中的textField？

Answer 1

<强> DetailViewController.h

@property (nonatomic , strong) NSString *myString; //Do this

<强> MasterViewController.m

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
    if ([[segue identifier] isEqualToString:@"showDetail"]) {

        NSIndexPath *indexPath = [self.tableView indexPathForSelectedRow];
        NSString *string = [feeds[indexPath.row] objectForKey: @"link"];

        //Do this
        APPDetailViewController *myController = (APPDetailViewController*)segue.destinationViewController;
        myController.myString = string;
    }
}

试试这种方式。

Answer 2

1 - theString内应该有DetailViewController个属性。（可选，请参阅下面的步骤3）

2 - 要编译和运行上述代码，您还必须将destinationViewController强制转换为DetailViewController。

像这样：

DetailViewController * destVC = (DetailViewController *) [segue destinationViewController];

3 -

destVC.theString = string;

可选地，theString内没有DetailViewController，您可以这样做：

destVC.textView.text = string;

使用prepareForSegue显示从MasterViewController到DetailViewController的字符串

2 个答案: