选择当前用户MySQL PHP的批准评论和未批准的评论

时间:2013-07-27 00:45:50

标签: php mysql select left-join

我是mysql的新手,我在从mysql数据库中选择数据时遇到了问题:

$post_id = 3;
$current_user_id = 1;

$query = "SELECT `comments`.*, `users`.`username`, `users`.`image` FROM (`comments`)
LEFT JOIN `users` ON `comments`.`user_id` = `users`.`id`
WHERE `comments`.`post_id` =  '$post_id'
AND `comments`.`status` =  1
AND `users`.`status` =  1
ORDER BY `comments`.`date` desc";

此选择,从数据库中选择所有已批准的注释,但在此选择中,我需要$ current_user_id的所有未批准的注释,

结果必须如下:

[所有已批准的帖子评论] + [所有未批准的$ current_user_id帖子评论]

2 个答案:

答案 0 :(得分:2)


不确定这是否真的有效,但只是试试看。我无法测试查询,因为我们没有架构。

SELECT `comments`.*, `users`.`username`, `users`.`image` FROM (`comments`)
LEFT JOIN `users` ON `comments`.`user_id` = `users`.`id`
WHERE `comments`.`post_id` =  '$post_id'
AND (
   (`comments`.`status` =  1 AND `users`.`status` =  1)
  OR
   ( `comments`.`status` =  0 AND `users`.`id`= '$current_user_id' )
)
ORDER BY `comments`.`date` desc

我的想法是选择所有approved comments OR(未经批准但来自此用户的评论)。你可能不得不改变查询,直到你得到你真正需要的东西,我只是给你这个想法,而不是确切的查询。希望这会对你有所帮助。

答案 1 :(得分:1)

SELECT `comments`.*, `users`.`username`, `users`.`image` FROM (`comments`)
LEFT JOIN `users` ON `comments`.`user_id` = `users`.`id`
WHERE `comments`.`post_id` =  '$post_id'
AND `comments`.`status` =  1
AND `users`.`status` =  1
UNION ALL
SELECT `comments`.*, `users`.`username`, `users`.`image` FROM (`comments`)
LEFT JOIN `users` ON `comments`.`user_id` = `users`.`id`
WHERE `comments`.`post_id` =  '$post_id'
AND `comments`.`status` =  0
AND `users`.`id` = '$current_user_id'
ORDER BY `comments`.`date` desc