Question

在我的控制器中，我有以下代码：

    public ActionResult Index(int? videoId, int languageId = 0)
        {

               //Some code 
        }

然后在我的.chtml页面中我这样引用它：

@using (Html.BeginForm("Index", "VideoLanguage", FormMethod.Post))
{
     @Html.Hidden("videoId", Model.VideoId)
     @Html.Hidden("videoLanguageId", Model.SelectedLanguage.LanguageId)

    <div>
        @Html.DropDownListFor(model => model.SelectedLanguage.LanguageId, ViewData["LanguageId"] as SelectList)
    </div>
    <div>
          <a href="@Url.Action("Index", "VideoLanguage",new { videoId = Model.VideoId, languageId = Model.SelectedLanguage.LanguageId })" class="linkbutton">Add Language</a>
    </div>

... code keeps going

那么当我点击按钮时会发生什么，从下拉列表中选择的LanguageId值不会通过。原始值是。

Answer 1

<a href="@Url.Action("Index", "VideoLanguage",new { videoId = Model.VideoId, languageId = Model.SelectedLanguage.LanguageId })" class="linkbutton">Add Language</a>

在页面加载时设置，因此HTML中的值将被硬编码。您需要做的是在Javascript中设置超链接参数或使用：

<input type="submit" value="Index" />

请参阅How to pass a textbox value from view to a controller in MVC 4?

Answer 2

试试这个：

@using (Html.BeginForm("Index", "VideoLanguage", FormMethod.Post, new { videoId = Model.VideoId, languageId = Model.SelectedLanguage.LanguageId }))
{
  ....
}

Answer 3

你应该将你的参数传递给@Html.BeginForm帮助器并提交表单

@using (Html.BeginForm("Index", "VideoLanguage", FormMethod.Post, new { videoId = Model.VideoId, languageId = Model.SelectedLanguage.LanguageId }))
{
     @Html.Hidden("videoId", Model.VideoId)
     @Html.Hidden("videoLanguageId", Model.SelectedLanguage.LanguageId)

    <div>
        @Html.DropDownListFor(model => model.SelectedLanguage.LanguageId, ViewData["LanguageId"] as SelectList)
    </div>
    <div>
       <input type="submit" value="Add Language"/>
    </div>

... code keeps going
}

在控制器中

，您还应该有两个方法GET和SET具有相同的名称：

public ActionResult Index()
        {
//Here just get a view
        }

[HttpPost]
public ActionResult Index(int? videoId, int languageId = 0)
        {
 //Here code to save in database
        }

Url.Action没有将参数传递给索引

3 个答案: