我有一个多维数组给我这个:
[ShipmentServiceLevelCategory] => test
[OrderTotal] => Array
(
[Amount] => 11.11
[CurrencyCode] => GBP
)
[ShipServiceLevel] => Std UK Dom
[MarketplaceId] => test
[ShippingAddress] => Array
(
[Phone] => 123213213213
[PostalCode] => TES T12
[Name] => Test
[CountryCode] => GB
[StateOrRegion] => Test
[AddressLine1] => Test
[City] => Test
)
我想将此信息插入到我的数据库中,但我的列名与数组键不同,因此我尝试创建另一个包含键映射的数组。这是我到目前为止所尝试的:
$map = array('ShippingAddress['Phone']' => 'DEL_PHONE','ShippingAddress['PostalCode']'=> 'DEL_POSTCODE','ShippingAddress['Name']' => 'DEL_NAME');
然而,这给了我一个语法错误,有人可以指出我在哪里错了吗?
答案 0 :(得分:0)
$map = array('ShippingAddress' => array (
'Phone' => 'DEL_PHONE',
'PostalCode' => 'DEL_POSTCODE',
'Name' => 'DEL_NAME'
) );
答案 1 :(得分:0)
这是获取当前数组值并在不同数组中使用它们的正确语法
$new_array = array();
$new_array['DEL_PHONE'] = $current_array['ShippingAddress']['Phone'];
$new_array['DEL_POSTCODE'] = $current_array['ShippingAddress']['PostalCode'];
这应该会让你对如何继续
有一个好主意答案 2 :(得分:0)
您可以制作如下数组:
define("DEL_PHONE", "col1");
define("DEL_NAME", "col2");
$attributes = array(
DEL_PHONE => $data['ShippingAddress']['Phone'],
DEL_NAME => $data['ShippingAddress']['PostalCode']
);