Question

我有一张桌子

ID NAME
--------
1  AAA
2  BBB
2  AAA
2  CCC
1  DDD
2  DDD

我必须显示与ID 1和2

链接的记录

NAME
----
AAA
DDD

我正在使用以下查询 -

Select Name from table1 where ID IN (1,2);

但它正在向我显示 -

NAME
-----
AAA
BBB
CCC
DDD

如何更改查询以解决此问题？

Answer 1

SELECT DISTINCT NAME
FROM tabel1 t1
join table1 t2
on t1.id = 1 and t2.id = 2 and t1.name = t2.name

或者如果可以有很多匹配

SELECT DISTINCT NAME
FROM tabel1 t1
WHERE EXISTS (SELECT 1 FROM table1 t2 WHERE t1.name = t2.name and t2.id = 2)
and t1.id = 1

或

SELECT NAME FROM tabel1 WHERE id = 1
INTERSECT
SELECT NAME FROM tabel1 WHERE id = 2

Answer 2

您需要按名称分组，然后计算您希望过滤的不同ID。

select name
from table
where id in (1,2)
group by name
having count (distinct ID) = 2

Answer 3

Select Name 
from table1 
where ID IN (1,2)
and Name in  ( select Name               
                 from table1 
                where ID IN (1,2)
               group by Name
               having count(id) =2 
             ) ;

Answer 4

Select Name from TableName 
where id in (1,2)
 group by Name having Count(Distinct Id)>1

Answer 5

select name 
from table t
where id = 1 and exists 
(select 1 from table where name = t.name and id = 2)

显示与两个ID链接的记录

5 个答案: