Question

我有一个包含电话号码的Application表。我正在尝试选择由ApplicationId降序排序的前10000行（以获取最新的应用程序），但我想删除所有重复的电话号码。

我试过了..

select distinct * from
(select top 10000 Forenames, PhoneNumber
from Application
order by ApplicationId desc) AS Applications

虽然此查询按Forename升序对其进行排序，即不再按ApplicationId顺序排序。

Answer 1

我认为您想要的逻辑是：获取每个电话号码的最新应用ID，然后返回有关这些电话号码的信息。

select a.*
from (select limit 10000 PhoneNumber, max(ApplicationId) as maxaid
      from Application a
      group by PhoneNumber
      order by max(aid) desc
     ) list join
     Application a
     on a.ApplicationId = list.maxaid
order by ApplicationId desc;

Answer 2

SELECT * FROM (select top 10000 Forenames, PhoneNumber, 
ROW_NUMBER() OVER(PARTITION BY PhoneNumber ORDER BY Forenames DESC) AS Row
from Application
order by ApplicationId desc) as temp
Where Row = 1

SQL选择行但删除具有重复电话号码的记录

2 个答案: