Question

第一个表（名为18_8_ChartOfAccounts），帐号如此

AccountNumber | VatReturnRowNumberForDebitTurnover
--------------------------------------------------
 1            |    not_blank
 2            |
 3            |    not_blank

第二个表（名为2_1_journal），如下所示

Amount | DebitAccount
----------------------
5     |  1
80    |  2
3     |  3
4     |  1
20    |  3

尝试获取以下内容：如果VatReturnRowNumberForDebitTurnover不为空/非空，请Amount求DebitAccount与（等于）AccountNumber相同。

或者想得到这样的输出：

Account number | Total
---------------------------
1              | 9 (5+4)
3              | 23 (20+3)

不需要回复帐户2的总计，因为帐户2 VatReturnRowNumberForDebitTurnover为空/空

此mysql查询从第一个表（AccountNumber）中选择所有 18_8_ChartOfAccounts

SELECT a.AccountNumber, IFNULL( d.Amount, 0 ) AS Amount 
FROM 18_8_ChartOfAccounts AS a 
LEFT JOIN ( SELECT DebitAccount, SUM( Amount ) AS Amount 
FROM ( SELECT * FROM 2_1_journal) DATA 
GROUP BY DebitAccount ) 
d ON (a.AccountNumber = d.DebitAccount)

但只需要选择AccountNumber，其中VatReturnRowNumberForDebitTurnover不为空/空

尝试修改mysql查询

SELECT a.AccountNumber, IFNULL( d.Amount, 0 ) AS Amount 
FROM 18_8_ChartOfAccounts AS a 

WHERE VatReturnRowNumberForDebitTurnover <> ''

LEFT JOIN ( SELECT DebitAccount, SUM( Amount ) AS Amount 
FROM ( SELECT * FROM 2_1_journal) DATA 
GROUP BY DebitAccount ) 
d ON (a.AccountNumber = d.DebitAccount)

获取Syntax error or access violation: ... near 'LEFT JOIN ( SELECT DebitAccount ....

然后更改了FROM 18_8_ChartOfAccounts AS a WHERE VatReturnRowNumberForDebitTurnover <> ''

到FROM 18_8_ChartOfAccounts WHERE VatReturnRowNumberForDebitTurnover <> '' AS a并收到类似的错误。

然后改为这样的代码：

SELECT a.AccountNumber, IFNULL( d.Amount, 0 ) AS Amount 
FROM 18_8_ChartOfAccounts AS a 
LEFT JOIN ( SELECT DebitAccount, SUM( Amount ) AS Amount 
FROM ( SELECT * FROM 2_1_journal) DATA 
WHERE a.VatReturnRowNumberForDebitTurnover <> "" 
GROUP BY DebitAccount ) 
d ON (a.AccountNumber = d.DebitAccount)

并获取Unknown column 'a.VatReturnRowNumberForDebitTurnover'

在表2_1_journal中没有这样的专栏。想要使用与a.VatReturnRowNumberForDebitTurnover相同的方式a.AccountNumber（两个列仅位于18_8_ChartOfAccounts。a.AccountNumber有效，a.VatReturnRowNumberForDebitTurnover无效。

请建议需要修改的内容

Answer 1

这应该有用;

SELECT AccountNumber, 
       CONCAT(SUM(Amount), ' (', GROUP_CONCAT(Amount SEPARATOR '+'), ')') Total
FROM 18_8_ChartOfAccounts
LEFT JOIN 2_1_journal
  ON AccountNumber = DebitAccount
WHERE VatReturnRowNumberForDebitTurnover IS NOT NULL
GROUP BY AccountNumber

An SQLfiddle to test with

当然，如果总结细节只是一个例子，你可以跳过GROUP_CONCAT()部分，然后使用......

SELECT AccountNumber, COALESCE(SUM(Amount), 0) Total
...

Another SQLfiddle

Answer 2

只需使用此查询：

SELECT a.AccountNumber, SUM( b.Amount ) AS Amount
  FROM 18_8_ChartOfAccounts AS a 
     LEFT JOIN 2_1_journal AS b ON a.AccountNumber = b.DebitAccount
        WHERE a.VatReturnRowNumberForDebitTurnover IS NOT NULL
        GROUP BY b.DebitAccount;

Answer 3

select
ca.AccountNumber,
sum(j.Amount)
from
18_8_ChartOfAccounts ca
left join 2_1_journal j on ca.AccountNumber = j.DebitAccount
where 
ca.VatReturnRowNumberForDebitTurnover is not null
group by ca.AccountNumber

看到它在sqlfiddle中正常工作。

MySQL从一个表的列中选择一些值（不是所有值），并根据所选值在其他表中求和值

3 个答案: