我制作了一个类模板来实现一个基于节点的"堆栈名为"mystack"
- :
template<typename T> class mystack;
template<typename T>ostream& operator <<(ostream& out,const mystack<T> &a);
template<typename T> struct mystack_node // The data structure for representing the "nodes" of the stack
{
T data;
mystack_node<T> *next;
};
template<typename T> class mystack
{
size_t stack_size; // A variable keeping the record of number of nodes present in the stack
mystack_node<T> *stack_top; // A pointer pointing to the top of the stack
/*
...
...( The rest of the implementation )
...
*/
friend ostream& operator << <T> (ostream&,const mystack&);
};
template<typename T>ostream& operator <<(ostream& out,const mystack<T> &a) // Output operator to show the contents of the stack using "cout"
{
mystack_node<T> *temp=a.stack_top;
while(temp!=NULL)
{
out<<temp->data<<" ";
temp=temp->next;
}
return out;
}
但我真正想要的是结构mystack_node
不应该可以访问代码的任何其他部分,除了类mystack
。所以我尝试了以下解决方法 - :
template<typename T> class mystack;
template<typename T>ostream& operator <<(ostream& out,const mystack<T> &a);
template<typename T> class mystack
{
struct mystack_node // The data structure for representing the "nodes" of the stack
{
T data;
mystack_node *next;
};
size_t stack_size; // A variable keeping the record of number of nodes present in the stack
mystack_node *stack_top; // A pointer pointing to the top of the stack
/*
...
...( The rest of the implementation )
...
*/
friend ostream& operator << <T> (ostream&,const mystack&);
};
template<typename T>ostream& operator <<(ostream& out,const mystack<T> &a) // Output operator to show the contents of the stack using "cout"
{
mystack<T>::mystack_node *temp=a.stack_top;
while(temp!=NULL)
{
out<<temp->data<<" ";
temp=temp->next;
}
return out;
}
但是我从编译器得到以下错误 - :
In function ‘std::ostream& operator<<(std::ostream&, const mystack<T>&)’:
error: ‘temp’ was not declared in this scope
有人可以告诉我们如何解决这个问题吗?
答案 0 :(得分:2)
正如评论中所提到的,我需要在temp的声明前插入关键字typename
:
typename mystack<T>::mystack_node *temp = a.stack_top;