我使用selenium和scrapy导航到数据表,我想将links / href解压缩到csv文件。到目前为止,我所尝试的一切似乎都不起作用,我不确定该尝试什么,或者如何获取链接。
这是表格的重要部分,我试图从中提取链接/ href:
<tr class="even">
<td class="paddingColumnValue"> </td>
<td class="nameColumnValue"><a href="/m/app?service=external/sdata_details&sp=12812" class="sdata" title="Click here for additional details.">click</a></td>
<td class="amountColumnValue">$600,000.00</td>
<td class="myListColumnValue"><a href="" onclick="doMyListButton(this.firstChild.getAttribute('src'),this.name);myListHandler(this.name);return false;" önmouseover="return true" name="12812"><img src="/m/images/add.gif" border="0" title="Click to add this to your list" name="A12812"></a></td>
</tr>
我最接近实际获取数据的是此代码...(注意表id = search_results)
import time
from scrapy.item import Item, Field
from selenium import webdriver
from scrapy.spider import BaseSpider
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
from scrapy.selector import HtmlXPathSelector
class ElyseAvenueItem(Item):
link = Field()
class ElyseAvenueSpider(BaseSpider):
name = "elyse"
allowed_domains = ["domain.com"]
start_urls = [
'http://www.domain.com']
def __init__(self):
self.driver = webdriver.Firefox()
def parse(self, response):
self.driver.get(response.url)
el1 = self.driver.find_element_by_xpath("//*[@id='headerRelatedLinks']/ul/li[5]/a")
el1.click()
time.sleep(2)
el2 = self.driver.find_element_by_xpath("/html/body/form/table/tbody/tr[2]/td[2]/table/tbody/tr/td[3]/p[3]/a[1]")
if el2:
el2.click()
time.sleep(2)
el3 = self.driver.find_element_by_xpath("/html/body/form/table/tbody/tr[2]/td[2]/table[1]/tbody/tr/td[3]/a")
if el3:
el3.click()
time.sleep(20)
titles = self.driver.find_elements_by_class_name("sdata")
items = []
for titles in titles:
item = ElyseAvenueItem()
item ["link"] = titles.find_element_by_xpath("//*[@id='search_results']/tbody/tr[2]/td[2]/a")
items.append(item)
return item
输出到csv: 位于0x03F16E90的selenium.webdriver.remote.webelement.WebElement对象
谢谢你的帮助。我可以发布更多我的尝试和他们的输出,如果这将有所帮助。就像我说的,我需要的是href,我只是无法弄清楚如何去做。
答案 0 :(得分:1)
您正在抓取selenium webelement实例而不是它的文本。替换:
item ["link"] = titles.find_element_by_xpath("//*[@id='search_results']/tbody/tr[2]/td[2]/a")
与
link = titles.find_element_by_xpath("//*[@id='search_results']/tbody/tr[2]/td[2]/a")
item ["link"] = link.get_attribute('href')
希望有所帮助。