Question

我需要一个表来提取信息。

SELECT [workID], [name], [status], [nextStep] FROM [JM_AccountWorkFlowDetail]

[nextStep]指向链中的下一步（如果可用）将匹配workID中的内容。

以上查询将返回：

workID  name                        status  nextStep
7       Name                        Status     0
9       Garnishment to Court        WWW        7

正如您在workID 9中看到的那样，它指向7，这意味着workID 7是列表中的下一个。

是否可以显示nextStep的名称而不是数字？

将返回以下内容的查询：

workID  name                        status  nextStep
7       Name                        Status     0
9       Garnishment to Court        WWW        Name

Answer 1

将其与表格本身相关联，以便通过将其与nextStep相关联来获取workid的名称。

SELECT  a.workID,
        a.name,
        a.status,
        COALESCE(b.name, CAST(a.nextStep AS VARCHAR(5))) nextStepName
FROM    JM_AccountWorkFlowDetail a
        LEFT JOIN JM_AccountWorkFlowDetail b
            ON a.nextStep = b.workID

Answer 2

   ; with
    cte1 as
    (
        SELECT 

        JM.[workID]
        ,JM.[name]
        ,JM.[status]
        ,(select top 1 name from JM_AccountWorkFlowDetail where nextStep = JM.nextStep) nextStep
        FROM [JM_AccountWorkFlowDetail] JM
    )

    select workid, name, status, case when nextstep=0 then 'no next step' else nextstep end
    from cte1

Answer 3

SELECT a.[workID], a.[name], a.[status], b.name as nextstep FROM [JM_AccountWorkFlowDetail] a
right outer join [JM_AccountWorkFlowDetail] b
on b.nextstep=a.nextstep

从同一个表中选择两次信息

3 个答案: