Question

我正在使用此代码：

$string = preg_replace("~(?!(?:https?://(?:www\.)?|www\.)(?:youtube\.com)(?:https?://(?:www\.)?|www\.)[\w./=?#-]+~i", '<a href="$0">$0</a>', $string);

这样我就可以将下方的链接转换为可点击的链接。

http://upload.wikimedia.org/wikipedia/commons/f/f2/Bill_Clinton%2C_Yitzhak_Rabin,%2C_Yasser_Arafat_at_the_White_House_1993-09-13.jpg

这适用于某个部分...它创建http://upload.wikimedia.org/wikipedia/commons/f/f2/Bill_Clinton的链接，但其余部分保留纯文本。如何使其适用于整个链接？所以你也看到comma ......我怎样才能建立一个链接？

Answer 1

此外，我还试图在网址末尾说明标点符号（以便我们不会将其包括在内）。

<?php

$string = "This works http://upload.wikimedia.org/wikipedia/commons/f/f2/Bill_Clinton%2C_Yitzhak_Rabin%2C_Yasser_Arafat_at_the_White_House_1993-09-13.jpg. This one should fail http://www.youtube.com/v/adlskdfjasopie. Although this one should fail as well http://youtu.be/adlkajdaslk.";

$string = preg_replace("~(?!(?:https?://(?:www\.)?|www\.)(?:youtu))(?:https?://(?:www\.)?|www\.)[^\s]+[^.!?,\<\]\[\)(]~i",'<a href="$0">$0</a>',$string);


?>

<强>输出

This works <a href="http://upload.wikimedia.org/wikipedia/commons/f/f2/Bill_Clinton%2C_Yitzhak_Rabin%2C_Yasser_Arafat_at_the_White_House_1993-09-13.jpg. ">http://upload.wikimedia.org/wikipedia/commons/f/f2/Bill_Clinton%2C_Yitzhak_Rabin%2C_Yasser_Arafat_at_the_White_House_1993-09-13.jpg. </a>This one should fail http://www.youtube.com/v/adlskdfjasopie. Although this one should fail as well http://youtu.be/adlkajdaslk.

正则表达式没有得到特殊字符的完整链接

1 个答案: