Question

我有班级人员。

Person.h

#import <Foundation/Foundation.h>

@interface Person : NSObject{
    NSString *name;
    NSString *screen_name;
}
@property (nonatomic, retain) NSString *name;
@property (nonatomic, retain) NSString *screen_name;

@end

Person.m

#import "Person.h"

@implementation Person

@synthesize text,screen_name;

@end

我有NSArray对象，带有值，例如text，screen_name等。

我做：

Person * person = object; ( object is NSArray)

我想获得价值，如下： person。名称，person。 screen_name

对象：

{
        "screen_name" = "mika_alcala";
        "text" ="";
        "time_zone" = "Eastern Time (US & Canada)";
        "url" = "<null>";
        "utc_offset" = "-14400";
        "verified" = 0;
};

Answer 1

好的，首先您不需要定义ivars，也不需要使用XCode 4.5+（IIRC）进行合成。

所以看起来应该......

Person.h

#import <Foundation/Foundation.h>

@interface Person : NSObject

@property (nonatomic, retain) NSString *name;
@property (nonatomic, retain) NSString *screen_name;

@end

Person.m

#import "Person.h"

@implementation Person

@end

对于实际问题，我不确定你在问什么。我要进一步询问......

编辑以显示如何从数组创建

首先关闭......

object :
{
        "screen_name" = "mika_alcala";
        "text" ="";
        "time_zone" = "Eastern Time (US & Canada)";
        "url" = "<null>";
        "utc_offset" = "-14400";
        "verified" = 0;
};

此对象实际上是NSDictionary而非NSArray。

有两种方法可以做到这一点......

创建一个空白Person对象，然后设置字典中的值。

Person *person = [[Person alloc] init];
person.name = object[@"screen_name"];
person.screen_name = object[@"screen_name"];

向Person对象添加自定义init方法。

Person.h

#import <Foundation/Foundation.h>

@interface Person : NSObject

@property (nonatomic, retain) NSString *name;
@property (nonatomic, retain) NSString *screen_name;

- (id)initWithDictionary:(NSDictionary *)dictionary;

@end

Person.m

#import "Person.h"

@implementation Person

- (id)initWithDictionary:(NSDictionary *)dictionary
{
    self = [super init];
    if (self) {
        _name = dictionary[@"screen_name"];
        _screen_name = dictionary[@"screen_name"];
    }
    return self;
}

@end

然后你就可以......

Person *person = [[Person alloc] initWithDictionary:object];

无论您采用哪种方法，您都可以获得person.name和person.screen_name。

如何从自定义类中读取值

1 个答案: