Question

select
    id,
    attempt,
    question,
    att_number,
    answer,
    timestamp,
    event
from
    mytable

在MSSQL 2008 R2中给出了这个输出：

id,attempt,question,seq_number,answer,timestamp,event
1296040,22059,3813,0,"11960,11961,11959,11958:",1265006717,0
1296165,22059,3813,1,"11960,11961,11959,11958:11960",1265011083,2
1296166,22059,3813,1,"11960,11961,11959,11958:11960",1265011049,6
1296163,22059,3813,1,"11960,11961,11959,11958:11960",1265011037,6
1296164,22059,3813,1,"11960,11961,11959,11958:11960",1265011072,6

如何仅为timestamp列的LOWEST值选择try，question，att_number，answer和event列的唯一行？

我想要这个：

id,attempt,question,seq_number,answer,timestamp,event
1296040,22059,3813,0,"11960,11961,11959,11958:",1265006717,0
1296165,22059,3813,1,"11960,11961,11959,11958:11960",1265011083,2
1296163,22059,3813,1,"11960,11961,11959,11958:11960",1265011037,6

Answer 1

您可以使用ranking function：

with cte as(
    select id,attempt,question,att_number,answer,timestamp,event,
           rn = Row_Number() Over (
                    Partition By attempt, question, att_number, answer,event 
                    Order By timestamp Asc)
    from mytable
)
select select,id,attempt,question,att_number,answer,timestamp,event
from cte
where rn = 1

如果您希望每个组中时间戳最短的所有记录都将Row_Number替换为Dense_Rank。

Answer 2

您必须使用group by子句。

以下select语句适用于您的示例。

select        
    min(id), attempt,question,
    att_number, answer, timestamp,
    event
from
    mytable
group by 
    attempt,question,
    att_number, answer, timestamp,
    event

但如果你真的想要最低的时间戳，你必须删除id列格式select，如下所示

select         
    attempt,question,
    att_number, answer, min(timestamp),
    event
from
    mytable
group by 
    attempt,question,
    att_number, answer,
    event

Answer 3

你需要使用GROUP BY和MIN：

select MIN(id),
       attempt,
       question,
       seq_number,
       answer,
       MIN(timestamp),
       event
  from mytable
  GROUP BY ATTEMPT, QUESTION, SEQ_NUMBER, ANSWER, EVENT

问题并不明显，但OP需要MIN（ID）和MIN（TIMESTAMP）。另请注意，示例结果中的列名称与OP的SQL中的列名称不同。我选择接受示例结果中的seq_number与原始SELECT语句中的att_number相同。

SQLFiddle here

分享并享受。

Answer 4

select
id,
attempt,
question,
att_number,
answer,
timestamp,
event
from
mytable m 
where m.timestamp=(
    select min(timestamp) 
    from mytable mi 
    where mi.attempt=m.attempt and mi.question=m.question and mi.att_number=m.att_number and mi.answer=m.answer and mi.event=m.event
)

Answer 5

使用distinct和order by statement。

SQL：选择唯一的行

5 个答案: