Question

我正在进行jquery分页，我在Json Response中返回要在特定页面和其他支持绑定元素值中加载的数据。为此，我需要在每次点击时返回一个二维数组作为Json响应。我已经声明了二维数组并将其返回到下面，我认为这样做的方式需要纠正。

我的php页面中的代码：

     header("Content-Type: application/json");   
 dataset array from which pagination will select the page data:

    $data = array("a","b","c","d","e","f","g","h","i","j",);

    2 dimensional array that I wish to return as response:

$response_multi = array(
    $currentPage,
    $hasNextPage,
    $hasPreviousPage,
    $maxPage,
    $dataCount,
    $dataResponse = array($pageSize),
    $pageSize   
);
    ######### variables and array within $response_multi array will be set and the return section is like ############

    echo json_encode($response_multi );

它不起作用。有人请！提前致谢。：）

Answer 1

试试这个

$pageSize = array(1,2,3,4)


$response_multi[] =  $currentPage;
$response_multi[] =  $hasNextPage;
$response_multi[] =  $hasPreviousPage;
$response_multi[] =  $maxPage;
$response_multi[] =  $dataCount;
$response_multi['dataResponse'] =  $pageSize;
$response_multi[] =  $pageSize;

echo json_encode($response_multi);

将多维数组作为json响应返回

1 个答案: