Question

我有一个查询，它给出了我的列名，数据类型，最大长度，可空......

如果列有外键，我还需要知道列引用的表的名称。

这是我的查询

SELECT 
  c.name 'Column Name',
  t.Name 'Data type',
  c.max_length 'Max Length',
  c.is_nullable,
  ISNULL(i.is_primary_key, 0) 'Primary Key'
FROM    
  sys.columns c
INNER JOIN 
  sys.types t ON c.system_type_id = t.system_type_id
LEFT OUTER JOIN 
  sys.index_columns ic ON ic.object_id = c.object_id AND ic.column_id = c.column_id
LEFT OUTER JOIN 
  sys.indexes i ON ic.object_id = i.object_id AND ic.index_id = i.index_id
WHERE
  c.object_id = OBJECT_ID('Table_Name')

Answer 1

感谢Devart，你让我走上了正确的道路。

以下是未来参考的答案

SELECT
      [Column Name] = c.name
    , [Data type] = t.name
    , [Max Length] = c.max_length
    , c.is_nullable
    , [Primary Key] = ISNULL(i.is_primary_key, 0)
    , OBJECT_NAME(fkc.referenced_object_id)
FROM sys.columns c WITH(NOWAIT)
JOIN sys.types t WITH(NOWAIT) ON c.system_type_id = t.system_type_id AND c.user_type_id = t.user_type_id
LEFT JOIN (
     SELECT i.[object_id], ic.column_id, i.is_primary_key
     FROM sys.indexes i WITH(NOWAIT)
     JOIN sys.index_columns ic WITH(NOWAIT) ON ic.[object_id] = i.[object_id] 
          AND i.index_id = ic.index_id
     WHERE i.is_primary_key = 1
) i ON c.[object_id] = i.[object_id] AND c.column_id = i.column_id
LEFT JOIN sys.foreign_key_columns fkc WITH(NOWAIT) ON fkc.parent_object_id = c.[object_id] 
     AND fkc.parent_column_id = c.column_id
WHERE c.[object_id] = OBJECT_ID('TableName')

Answer 2

试试这个 -

SELECT
      [Column Name] = c.name
    , [Data type] = t.name
    , [Max Length] = c.max_length
    , c.is_nullable
    , [Primary Key] = ISNULL(i.is_primary_key, 0)
    , IsFK = ISNULL(fkc.parent_object_id / fkc.parent_object_id, 0)
FROM sys.columns c WITH(NOWAIT)
JOIN sys.types t WITH(NOWAIT) ON c.system_type_id = t.system_type_id AND c.user_type_id = t.user_type_id
LEFT JOIN (
     SELECT i.[object_id], ic.column_id, i.is_primary_key
     FROM sys.indexes i WITH(NOWAIT)
     JOIN sys.index_columns ic WITH(NOWAIT) ON ic.[object_id] = i.[object_id] 
          AND i.index_id = ic.index_id
     WHERE i.is_primary_key = 1
) i ON c.[object_id] = i.[object_id] AND c.column_id = i.column_id
LEFT JOIN sys.foreign_key_columns fkc WITH(NOWAIT) ON fkc.parent_object_id = c.[object_id] 
     AND fkc.parent_column_id = c.column_id
WHERE c.[object_id] = OBJECT_ID('Table_Name')

列的键是什么表

2 个答案: