Question

我想将用于放入x的内容放在yourNumbers数组中，我该怎么做？编辑：如何使用循环清理底部的println部分。

import java.util.Scanner; 
 public class array {
public class SS_Un8As1 {
public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    int[] yourNumbers = new int[10];
    for (int counter=0; counter < yourNumbers.length; counter++){
        System.out.print("Enter your number: ");
        yourNumbers[counter] = scan.nextInt();
     }         
   System.out.println("Original numbers: " + yourNumbers[0] + "," + yourNumbers[1] + "," + yourNumbers[2] + "," + yourNumbers[3] + "," + yourNumbers[4] + "," + yourNumbers[5] + "," + yourNumbers[6] + "," + yourNumbers[7] + "," + yourNumbers[8] + "," + yourNumbers[9]);
   System.out.println("Original numbers multiplied by five: " + yourNumbers[0]*5 + "," + yourNumbers[1]*5 + "," + yourNumbers[2]*5 + "," + yourNumbers[3]*5 + "," + yourNumbers[4]*5 + "," + yourNumbers[5]*5 + "," + yourNumbers[6]*5 + "," + yourNumbers[7]*5 + "," + yourNumbers[8]*5 + "," + yourNumbers[9]*5);
   System.out.println("Original numbers minus the next number: " + (yourNumbers[0]-yourNumbers[1]) + "," + (yourNumbers[1]-yourNumbers[2]) + "," + (yourNumbers[2]-yourNumbers[3]) + "," + (yourNumbers[3]-yourNumbers[4]) + "," + (yourNumbers[4]-yourNumbers[5]) + "," + (yourNumbers[5]-yourNumbers[6]) + "," + (yourNumbers[6]-yourNumbers[7]) + "," + (yourNumbers[7]-yourNumbers[8]) + "," + (yourNumbers[8]-yourNumbers[9]) + "," + (yourNumbers[9]-yourNumbers[0]));
}

}

Answer 1

像这样：

yourNumbers[counter] = x;

上面的代码说明：将x的值存储在索引（位置）yourNumbers中的数组counter中。因为counter是for循环的迭代变量，所以每次循环前进计数器时，x的下一个值将存储在数组中的下一个可用位置。

您必须确保数组的长度与counter的值相同。在您的代码中，执行以下操作：

int[] yourNumbers = new int[10];

为什么呢？因为counter从0转到9，所以数组的长度必须为10。

Answer 2

替换此

int x = scan.nextInt();

与

yourNumbers[counter] = scan.nextInt();

此外，条件应为counter<9，或更好counter<yourNumbers.length

Answer 3

只需将输入传递到数组的下一个元素，而在for循环中：

yourNumbers[counter] = x;

但是，我还应该指出，在分配x值之前，您应该验证输入实际上是一个整数。如果该值不是整数，则程序将崩溃。

将用户创建的变量放在数组中

3 个答案: