我正在尝试验证:我尝试创建的文件夹是否存在。当然,我收到一条消息......一条错误信息:/告诉我它! (如果它不存在,没有错误信息,一切都按计划进行)。
它输出此错误消息
Directory exists
Warning: mkdir() [function.mkdir]: File exists in /home/***/public_html/***/formulaires/processForm-test.php on line 75
UPLOADS folder has NOT been created
我使用的当前代码就是这个:
$dirPath = $_POST['company'];
if(is_dir($dirPath))
echo 'Directory exists';
else
echo 'directory not exist';
function ftp_directory_exists($ftp, $dirPath)
{
// Get the current working directory
$origin = ftp_pwd($ftp);
// Attempt to change directory, suppress errors
if (@ftp_chdir($ftp, $dirPath))
{
// If the directory exists, set back to origin
ftp_chdir($ftp, $origin);
return true;
}
// Directory does not exist
return false;
}
$result = mkdir($dirPath, 0755);
if ($result == 1) {
echo '<br/>'.$dirPath . " has been created".'<br/>';
} else {
echo '<br/>'.$dirPath . " has NOT been created".'<br/>';
}
我最近添加了中间部分(我不知道这是否会产生影响)。以“function ftp_directory_exists($ ftp,$ dirPath)”开头的那个“
答案 0 :(得分:1)
使用file_exists()
检查文件/目录是否存在:
if(!file_exists('/path/to/your/directory')){
//yay, the directory doesn't exist, continue
}
答案 1 :(得分:1)
您添加的函数ftp_directory_exists不会对您的代码产生任何影响,因为它永远不会被调用...
您可能会尝试这样的事情(未经过测试......):
$dirPath = $_POST['company'];
$dirExists = is_dir($dirPath);
if(!dirExists)
$dirExists = mkdir($dirPath, 0755);
echo '<br/>'.$dirPath . (($dirExists)? "" : "DO NOT") . " exists".'<br/>';