Question

我有一系列datetime64 [ns]对象。

我想提取日期和分钟（HH：MM）部分。到目前为止，我正在使用下面的代码，但它非常慢。我怎么能更有效地做到这一点？

>>> type(df['EXECUTION_TIMESTAMP'])
Out[1]: pandas.core.series.Series


>>> df['EXECUTION_TIMESTAMP']
Out[1]: 
0    2012-12-13 16:46:37
1    2012-12-13 16:46:42
2    2012-12-13 16:46:47

...

68   2010-09-07 15:21:38
69   2013-07-21 21:40:14
70   2010-07-21 22:44:46
Name: EXECUTION_TIMESTAMP, Length: 769552, dtype: datetime64[ns]


# Get the DateTimes Only
ets = pd.Series(df['EXECUTION_TIMESTAMP'])

print('Converting times')
dt_min = []
dd     = []
for x in ets:
    dt_min.append(pd.datetime(2000,1,1,x.hour,x.minute))
    dd.append(pd.datetime(x.year,x.month,x.day))

Answer 1

In [1]: df = DataFrame(dict(time = Series([Timestamp('20121213 16:46:37'),Timestamp('20121213 16:46:42'),Timestamp('20121213 16:46:47'),Timestamp('20100907 16:21:38')])))

In [2]: df
Out[2]: 
                 time
0 2012-12-13 16:46:37
1 2012-12-13 16:46:42
2 2012-12-13 16:46:47
3 2010-09-07 16:21:38

In [3]: df.dtypes
Out[3]: 
time    datetime64[ns]
dtype: object

In [4]: index = pd.DatetimeIndex(df['time'])

In [5]: index
Out[5]: 
<class 'pandas.tseries.index.DatetimeIndex'>
[2012-12-13 16:46:37, ..., 2010-09-07 16:21:38]
Length: 4, Freq: None, Timezone: None

In [6]: zip(index.minute,index.second)
Out[6]: [(46, 37), (46, 42), (46, 47), (21, 38)]

不显示元组列表，而是显示小时，分钟提取的日期

In [10]: Series([ datetime.datetime(2000,1,1,t.hour,t.minute) for t in pd.DatetimeIndex(df['time']).time ])
Out[10]: 
0   2000-01-01 16:46:00
1   2000-01-01 16:46:00
2   2000-01-01 16:46:00
3   2000-01-01 16:21:00
dtype: datetime64[ns]

我猜你最终想要分组;直接做到这一点

df.set_index('time').groupby(lambda x: x.hour,lambda x: x.minute).apply(...)

Python，将datetime64的系列转换为日期和分钟

1 个答案: