Question

我想像整数一样使用$ 1值我们的想法是用原始文本替换所有数字和等效的数组值，并创建一个新文本下面想要的结果应该是“这是DBValue4，这是DBValue2，这是DBValue7”
另外，有没有办法保存这些反向引用以供进一步使用？

String[] values = {"DBValue0","DBValue1","DBValue2","DBValue3","DBValue4","DBValue5","DBValue6","DBValue7","DBValue8","DBValue9","DBValue10"};
String originaltext = "This is 4, This is 2, This is 7";
text = originaltext.replaceAll("(\\d)","$1");
// want something like
text = originaltext.replaceAll("(\\d)",values[$1]);
//or
text = originaltext.replaceAll("(\\d)",values[Integer.parseInt("$1")]);

Answer 1

您可以像这样使用Pattern和Matcher：

public static void main(String[] args) throws Exception {
    final String[] values = {"DBValue0", "DBValue1", "DBValue2", "DBValue3", "DBValue4", "DBValue5", "DBValue6", "DBValue7", "DBValue8", "DBValue9", "DBValue10"};
    final String originaltext = "This is 4, This is 2, This is 7";
    final Pattern pattern = Pattern.compile("(?<=This is )\\d++");
    final Matcher matcher = pattern.matcher(originaltext);
    final StringBuffer sb = new StringBuffer();
    while (matcher.find()) {
        System.out.println(matcher.group());
        final int index = Integer.parseInt(matcher.group());
        matcher.appendReplacement(sb, values[index]);
    }
    matcher.appendTail(sb);
    System.out.println(sb);
}

输出：

4
2
7
This is DBValue4, This is DBValue2, This is DBValue7

修改

OP的注释似乎OP需要替换String形式的{name, index}，其中“name”是数组的名称，“index”是元素的索引在那个数组中。

通过Map使用Map<String, String[]>将数组ping到其名称，然后使用Pattern首先捕获name然后index，可以轻松实现此目的。 }。

public static void main(String[] args) throws Exception { final String[] companies = {"Company1", "Company2", "Company3"}; final String[] names = {"Alice", "Bob", "Eve"}; final String originaltext = "This is {company, 0}, This is {name, 1}, This is {name, 2}"; final Map<String, String[]> values = new HashMap<>(); values.put("company", companies); values.put("name", names); final Pattern pattern = Pattern.compile("\\{([^,]++),\\s*+(\\d++)}"); final Matcher matcher = pattern.matcher(originaltext); final StringBuffer sb = new StringBuffer(); while (matcher.find()) { System.out.println(matcher.group(1)); System.out.println(matcher.group(2)); final int index = Integer.parseInt(matcher.group(2)); matcher.appendReplacement(sb, values.get(matcher.group(1))[index]); } matcher.appendTail(sb); System.out.println(sb); }

输出：

company 0 name 1 name 2 This is Company1, This is Bob, This is Eve

在正则表达式中使用反向引用来动态替换文本

1 个答案: