我已经完成了一个测验程序..任何人都可以帮助我如何在用户点击错误答案时显示分数？也因为我使用了随机功能，任何人都可以告诉我如何避免两个选项重复，因为我也有这个问题..
import sys, pygame,random
from pygame.locals import *
#set up screen size
size1 = width, height = 600,600
# set up pygame, the window, and the mouse cursor
pygame.init()
pygame.mixer.init()
mainClock = pygame.time.Clock()
screen = pygame.display.set_mode(size1)
pygame.display.set_caption('Know World Capitals')
#set up colors
WHITE=255,255,255
BLACK = 35, 35, 35
GREY=215,215,215
ORANGE=246,173,70
#screen color
background = pygame.image.load("bckgrnd.jpg")
backgroundRect = background.get_rect()
background2 = pygame.image.load("bckgrnd2.jpg")
background2Rect = background2.get_rect()
#set up fonts
font1 = pygame.font.SysFont('ORW Gothic L',48)
font2 = pygame.font.SysFont('ORW Gothic L',22)
font3 = pygame.font.SysFont('ORW Gothic L',30)
#load game sounds
wow= pygame.mixer.Sound('wow.wav')
oops= pygame.mixer.Sound('lose.mp3')
#load first set of pics
a = pygame.image.load("b.jpg")
aRect = a.get_rect()
aRect.topleft=20,200
b = pygame.image.load("b.jpg")
bRect = b.get_rect()
bRect.topleft=20,230
c= pygame.image.load("b.jpg")
cRect = c.get_rect()
cRect.topleft=20,260
d = pygame.image.load("b.jpg")
dRect = d.get_rect()
dRect.topleft=20,290
#load 2nd set of pics
f = pygame.image.load("a.jpg")
fRect = f.get_rect()
fRect.topleft=20,200
g = pygame.image.load("a.jpg")
gRect = g.get_rect()
gRect.topleft=20,230
h= pygame.image.load("a.jpg")
hRect = h.get_rect()
hRect.topleft=20,260
j= pygame.image.load("a.jpg")
jRect = j.get_rect()
jRect.topleft=20,290
#load screen1 pic
e = pygame.image.load("fg2.png")
eRect = e.get_rect()
eRect.topleft=175,100
#mouse pics
p=Rect(20, 200,215,30)
r=Rect(20,230, 215,30)
s=Rect(20,260, 215,30)
t=Rect(20,290, 215,30)
u=Rect( 545,475,70,31)
#a list of the 51 countries
S=['Jordan','Kazhakstan','Vietnam','Azerbaijan','Hungary','Libya','Seychelles','Cuba','Columbia','Venezuela','Madagascar','Israel','Qatar','Syria','Cyprus','Bahrain','Bulgaria','Belgium','Egypt','Barbados','Jamaica','Canada','Argentina','Chile','Peru','Honduras','Iceland','Saudi Arabia','Turkey','Thailand','Japan','India','Phillipines','Croatia','Greece','Romania','Finland','Russia','Lebanon','Uzbekistan','Bhutan','Bangladesh','Macedonia','Latvia','Ukraine','Slovakia','Norway','Poland','Lithuania','Mauritius','Kenya']
#a list of the 51 capitals
C=['Amman','Akmola','Hanoi','Baku','Budapest','Tripoli','Tripoli','Havana','Bogota','Caracas','Antananarivo','Jerusalem','Doha','Damascus','Nicosia','Manama','Sofia','Brussels','Cairo','Bridgetown','Kingston','Ottawa','Buenos Aires','Santiago','Lima','Tegucigalpa','Reykjavik','Riyadh','Ankara','Bangkok','Tokyo','New Delhi','Manila','Zagreb','Athens','Bucharest','Helsinki','Moscow','Beirut','Tashkent','Thimphu','Dhaka','Skopje','Riga','Kiev','Bratislava','Oslo','Warsaw','Vilnius','Port Louis','Nairobi']
#get random place form a list
def getRanP(myList):
# This function returns a random state or capitol from the passed list.
key = random.randint(0, len(myList) - 1)
place=myList[key]
return place
#the game ends if this function is called
def terminate():
pygame.quit()
sys.exit()
#checks if player wants to quit the game
def waitForPlayerToPressKey():
while True:
for event in pygame.event.get():
if event.type == QUIT:
terminate()
elif event.type == KEYDOWN:
if event.key == ord('w'): # pressing escape quits
terminate()
return
#sets up grey colored text when given the text,font,surface and the x,y cordinates as attributes
def drawText1(text, font, surface, x, y):
w = font.render(text, 1, WHITE)
v = w.get_rect()
v.topleft = (x, y)
surface.blit(w,v)
#creates black-colored text when given the text,font,surface and the x,y cordinates as attributes
def drawText2(text, font, surface, x, y):
w = font.render(text, 1, WHITE)
v = w.get_rect()
v.topleft = (x, y)
surface.blit(w,v)
#game screens
#set-up first screen
def screen1():
screen.blit(background2, background2Rect)
pygame.mixer.music.load("www.ogg")
pygame.mixer.music.play(0)
pygame.display.flip()
waitForPlayerToPressKey()
#draw screen if player chooses a correct state
def screen3(cS,cC):
screen.blit(background, backgroundRect)
drawText1('Y o u g o t i t !...,',font1,screen,175,120)
drawText1(cC,font3,screen,250,210)
drawText2('i s t h e C a p i t a l o f ',font2,screen,125,245)
drawText1(cS,font3,screen,325,245)
drawText1('P r e s s a n y k e y t o C o n t i n u e . . .',font2,screen,150,330)
drawText2('O r P r e s s W t o Q u i t',font2,screen,165,385)
pygame.display.flip()
waitForPlayerToPressKey()
#draw screen if player chooses the wrong state
def screen4(cS,cC):
screen.blit(background, backgroundRect)
drawText1('Oops!...,',font1,screen,175,120)
drawText1(cC,font3,screen,250,210)
drawText2('i s t h e C a p i t a l o f ',font2,screen,125,245)
drawText1(cS,font3,screen,325,245)
drawText1('P r e s s a n y k e y t o Q u i t . . .',font2,screen,150,330)
pygame.display.flip()
waitForPlayerToPressKey()
#check if player has clicked on the right or wrong state
def check(v,cap,s,cS):
waitForPlayerToPressKey()
if C.index(cap)==S.index(s):
#play sound and draw screen3 if player has clicked on the right state
pygame.mixer.music.load("wow.ogg")
pygame.mixer.music.play(0)
screen3(cS,cap)
changeCol()
else:
#play sound and draw screen4 if player has clicked on the wrong state
pygame.mixer.music.load("lose.ogg")
pygame.mixer.music.play(0)
screen4(cS,cap)
terminate()
#main game screen
def changeCol():
pygame.mixer.music.load("next.ogg")
pygame.mixer.music.play(0)
capitol=getRanP(C)
n=C.index(capitol)
y = random.randint(0, 4)
key=n
x=random.randint(0,5)
S[n]=S[C.index(capitol)]
cS=S[n]
screen.blit(background, backgroundRect)
drawText2(capitol+' is the capital of ?', font1, screen,35,90)
#draw game-block choises on screen
screen.blit(a,aRect)
screen.blit(b,bRect)
screen.blit(c,cRect)
screen.blit(d,dRect)
drawText1('C l i c k ',font2,screen,250,410)
drawText1('O n t h e S t a t e t h a t H a s t h e a b o v e C a p i t a l',font2,screen,90,440)
drawText1('t h e n P r e s s a n y k e y t o C o n t i n u e . . . ',font2,screen,140,470)
#draw choises
#randomly position the correct state in any of the choise blocks
if y==0:
rdS1=S[n]
rdS2=S[random.randint(0,17)]
rdS3=S[random.randint(17,34)]
rdS4=S[random.randint(34,50)]
drawText1(rdS1, font2, screen,25,205)
drawText1(rdS2, font2, screen,25,235)
drawText1(rdS3, font2, screen,25,265)
drawText1(rdS4, font2, screen,25,295)
pygame.display.update()
elif y==1:
rdS1=S[random.randint(0,17)]
rdS2=S[n]
rdS3=S[random.randint(17,34)]
rdS4=S[random.randint(34,50)]
drawText1(rdS1, font2, screen,25,205)
drawText1(rdS2, font2, screen,25,235)
drawText1(rdS3, font2, screen,25,265)
drawText1(rdS4, font2, screen,25,295)
pygame.display.update()
elif y==2:
rdS1=S[random.randint(0,17)]
rdS2=S[random.randint(17,34)]
rdS3=S[n]
rdS4=S[random.randint(34,50)]
drawText1(rdS1, font2, screen,25,205)
drawText1(rdS2, font2, screen,25,235)
drawText1(rdS3, font2, screen,25,265)
drawText1(rdS4, font2, screen,25,295)
pygame.display.update()
else:
rdS1=S[random.randint(0,17)]
rdS2=S[random.randint(17,34)]
rdS3=S[random.randint(34,50)]
rdS4=S[n]
drawText1(rdS1, font2, screen,25,205)
drawText1(rdS2, font2, screen,25,235)
drawText1(rdS3, font2, screen,25,265)
drawText1(rdS4, font2, screen,25,295)
pygame.display.update()
while True:
#check which button the player clicks
for event in pygame.event.get():
if event.type == pygame.QUIT: sys.exit()
elif event.type == MOUSEBUTTONDOWN:
#return the poistion of the mouse
z=pygame.mouse.get_pos()
#when the player clicks on a button,change color of the button to white, check if the state the player has chosen is right or wrong & then ask him another question
if (p.collidepoint(z)):
screen.blit(f,fRect)
pygame.display.update()
check(n,capitol,rdS1,cS)
elif (r.collidepoint(z)):
screen.blit(g,gRect)
pygame.display.update()
check(n,capitol,rdS2,cS)
elif (s.collidepoint(z)):
screen.blit(h,hRect)
pygame.display.update()
check(n,capitol,rdS3,cS)
elif (t.collidepoint(z)):
screen.blit(j,jRect)
pygame.display.update()
check(n,capitol,rdS4,cS)
#main game loop
screen1()
changeCol()
答案 0 :(得分：2)
为防止出现双重问题，我会使用您的国家/资本列表的其他解决方案。 我不会创建两个列表，而是创建一个这样的字典：
d = {'Jordan':'Amman',
'Kazhakstan':'Akmola',
'Vietnam':'Hanoi',
'Azerbaijan':'Baku',
'Hungary':'Budapest'}
在多米尼克的评论之后编辑
每次运行程序时都使用此命令获取不同的顺序而不重复选项：
import random
countries = list(d)
random.shuffle(countries)
for country in countries:
# Here your game code...
print("Capital of {0} is {1}".format(country, d[country]))
答案 1 :(得分：1)
这只是一个使用字典和生成器产生随机资本的例子。
import random
d = {'Amman':'Jordan',
'Akmola':'Kazhakstan',
'Hanoi':'Vietnam',
'Baku':'Azerbaijan',
'Budapest':'Hungary'}
def gen_capital(d):
"Generator that yields a random capital"
# Get the capitals
capitals = list(d)
# Shuffle the capitals in a random order
random.shuffle(capitals)
# Yield all the capitals in the list one by one
for capital in capitals:
yield capital
def get_answers(countries, correct):
# Choose 3 random answers
answers = random.sample(countries, 3)
# Make sure the right answer is in the answer list
if not correct in answers:
answers[random.randint(0, 2)] = correct
return answers
random_capital = gen_capital(d)
countries = list(d.values())
在您的代码中，您可以使用类似的
来请求下一个资本try:
capital = next(random_capital)
except StopIteration:
pass # All capitals are asked..
接下来，使用get_answers(countries, d[capital])
注意：我使用了3个可能的答案，但我认为如何在4个答案中更改这个答案。
作为示例/测试，您可以循环查看这是如何生成随机资本的，随机答案没有重复：
for capital in random_capital:
print("{0} is the capital of ? ({1})".format(
capital, ", ".join(get_answers(countries, d[capital]))))
# Budapest is the capital of ? (Hungary, Vietnam, Jordan)
# Baku is the capital of ? (Jordan, Azerbaijan, Vietnam)
# Akmola is the capital of ? (Kazhakstan, Azerbaijan, Jordan)
# Hanoi is the capital of ? (Vietnam, Jordan, Azerbaijan)
# Amman is the capital of ? (Hungary, Kazhakstan, Jordan)