我是春天的3.2。这是我的配置文件
<bean id="legacyDataSource" name="legacydb" class="org.springframework.jdbc.datasource.DriverManagerDataSource" lazy-init="true">
<property name="driverClassName" value="${jdbc.legacy.driverClassName}" />
<property name="url" value="${jdbc.legacy.url}" />
<property name="username" value="${jdbc.legacy.username}" />
<property name="password" value="${jdbc.legacy.password}" />
</bean>
<bean id="ls360DataSource" name="Ls360db" class="org.springframework.jdbc.datasource.DriverManagerDataSource" lazy-init="true" >
<property name="driverClassName" value="${jdbc.ls360.driverClassName}" />
<property name="url" value="${jdbc.ls360.url}" />
<property name="username" value="${jdbc.ls360.username}" />
<property name="password" value="${jdbc.ls360.password}" />
</bean>
<bean id="legacyTransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="legacyEmf"/>
</bean>
<bean id="ls360TransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="ls360Emf"/>
</bean>
<tx:annotation-driven transaction-manager="transactionManager" />
<bean id="legacyEmf" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean" >
<property name="dataSource" ref="legacyDataSource" />
<property name="jpaVendorAdapter" ref="vendorAdaptor" />
<property name="packagesToScan" value="com.softech.ls360.integration.regulators.plcb.domain"/>
<property name="jpaProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</prop>
<prop key="hibernate.max_fetch_depth">3</prop>
<prop key="hibernate.jdbc.fetch_size">50</prop>
<prop key="hibernate.jdbc.batch_size">10</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="ls360Emf" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean" >
<property name="dataSource" ref="ls360DataSource" />
<property name="jpaVendorAdapter" ref="vendorAdaptor" />
<property name="packagesToScan" value="com.softech.ls360.integration.regulators.plcb.domain"/>
<property name="jpaProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</prop>
<prop key="hibernate.max_fetch_depth">3</prop>
<prop key="hibernate.jdbc.fetch_size">50</prop>
<prop key="hibernate.jdbc.batch_size">10</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<context:component-scan base-package="....db" />
这是我的班级
@Service("dbManager")
@Repository
@Transactional
public class DatabaseManager {
@PersistenceContext
@Qualifier("legacyEmf")
private EntityManager legacyEm;
@PersistenceContext
@Qualifier("ls360Emf")
private EntityManager ls360Em;
@SuppressWarnings("unchecked")
@Transactional(readOnly=true)
public List<Object> getResultList(String query, Class mappingClass) throws Exception {
//Query emQuery = legacyEm.createNativeQuery(query, mappingClass);
//return emQuery.getResultList();
return null;
} //end of findTraineeFromLegacy()
}
现在,当我朗读代码时,我收到以下错误
Error creating bean with name 'dbManager': Injection of persistence
dependencies failed; nested exception is
org.springframework.beans.factory.NoUniqueBeanDefinitionException:
No qualifying bean of type [javax.persistence.EntityManagerFactory] is defined:
expected single matching bean but found 2: legacyEmf,ls360Emf
为什么我收到此错误。我该如何解决?
由于
答案 0 :(得分:19)
我今天遇到了同样的问题。解决了它做到以下几点:
首先,我将参数unitName添加到@PersistenceContext到两个实体管理器属性:
@PersistenceContext(unitName="appPU")
@Qualifier(value = "appEntityManagerFactory")
private EntityManager appEntityManager;
@PersistenceContext(unitName="managerPU")
@Qualifier(value = "managerEntityManagerFactory")
private EntityManager managerEntityManager;
在我的配置文件中,我已经将属性persistenceUnitName添加到我的bean定义中:
<bean id="appEntityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource1" />
<property name="persistenceUnitName" value="appPU" />
<property name="packagesToScan" value="br.com.app.domain" />
...
</bean>
<bean id="managerEntityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource2" />
<property name="persistenceUnitName" value="managerPU" />
<property name="packagesToScan" value="br.com.app.domain" />
...
</bean>
答案 1 :(得分:4)
此外,我还想再添加一些有用的评论:您需要扩展网络应用的“web.xml”文件中的部分。从现在开始,您有2个实体管理器,您需要2个OpenEntityManagerInViewFilters。看一下这个例子:
<filter>
<filter-name>OpenEntityManagerInViewFilter1</filter-name>
<filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
<init-param>
<param-name>entityManagerFactoryBeanName</param-name>
<param-value>appEntityManagerFactory</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>OpenEntityManagerInViewFilter1</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<filter>
<filter-name>OpenEntityManagerInViewFilter2</filter-name>
<filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
<init-param>
<param-name>entityManagerFactoryBeanName</param-name>
<param-value>managerEntityManagerFactory</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>OpenEntityManagerInViewFilter2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
注意&lt;&lt;&lt;&lt;&lt; param-value&gt; appEntityManagerFactory&lt; / param-value&gt; ='appEntityManagerFactory'in&lt; bean id =“appEntityManagerFactory”。
答案 2 :(得分:2)
我也遇到了这样的问题并解决了它。请执行以下操作来解决此错误:
将以下行添加到两个架构的所有实体类中。
@PersistenceContext(unitName="<persistenceUnit>")
transient EntityManager entityManager;
<persistenceUnit>
是您在persistence.xml
文件中定义的持久性单元的名称。