Question

我有下面提到的格式的数据，当我试图插入表格时我收到错误

ORA-01858: a non-numeric character was found where a numeric was expected

如何成功将记录插入表格？

create table mytab (dt timestamp(0));

Insert into mytab
   (dt)
 Values
   (TO_TIMESTAMP('16/JUL/13 2:53:08. PM','DD/MON/YY fmHH12fm:MI:SS.FF AM'));

Answer 1

您需要指定零小数秒。这是你的错误：

SQL> create table mytab (dt timestamp(0));

Table created.

SQL> Insert into mytab
   (dt)
 Values
   (TO_TIMESTAMP('16/JUL/13 2:53:08. PM','DD/MON/YY fmHH12fm:MI:SS.FF AM'));   2    3    4  
   (TO_TIMESTAMP('16/JUL/13 2:53:08. PM','DD/MON/YY fmHH12fm:MI:SS.FF AM'))
                 *
ERROR at line 4:
ORA-01858: a non-numeric character was found where a numeric was expected

SQL>

让我们修复输入

SQL> ed
Wrote file afiedt.buf

  1  Insert into mytab
  2     (dt)
  3   Values
  4*    (TO_TIMESTAMP('16/JUL/13 2:53:08.00 PM','DD/MON/YY fmHH12fm:MI:SS.FF AM'))
SQL> r
  1  Insert into mytab
  2     (dt)
  3   Values
  4*    (TO_TIMESTAMP('16/JUL/13 2:53:08.00 PM','DD/MON/YY fmHH12fm:MI:SS.FF AM'))

1 row created.

SQL>

因此，即使您指定了零精度的时间戳，您的输入仍需要与掩码匹配。这意味着您需要.00来匹配.FF。

或者，不要费心包括小数秒：

SQL> ed
Wrote file afiedt.buf

  1  insert into mytab
  2     (dt)
  3   Values
  4*    (TO_TIMESTAMP('16/JUL/13 2:53:08 PM','DD/MON/YY fmHH12fm:MI:SS AM'))
SQL> r
  1  insert into mytab
  2     (dt)
  3   Values
  4*    (TO_TIMESTAMP('16/JUL/13 2:53:08 PM','DD/MON/YY fmHH12fm:MI:SS AM'))

1 row created.

SQL>

顺便说一句，请注意TIMESTAMP（0）将绕过任何小数秒，在半秒内向上舍入。这是否重要取决于您将如何填充列以及需要准确的时间。

Answer 2

你需要第二部分：

Insert into mytab(dt)
 Values
    (TO_TIMESTAMP('16/JUL/13 2:53:08.00 PM','DD/MON/YY fmHH12fm:MI:SS.FF AM'));

Answer 3

你有一个“。”分钟后

这是有效的

select TO_TIMESTAMP('16/JUL/13 2:53:08 PM','DD/MON/YY fmHH12fm:MI:SS.FF AM') 
from dual

ORA-01858：尝试插入时间戳（0）列时出错

3 个答案: