Question

我有以下代码：

CASE WHEN (1+sum(x)/sum(y)) >=0 and (1+sum(x)/sum(y)) < 0.5 Then 1 ELSE 0

x和y是列。我的问题是，sum(y)可以是0，我得到的错误除以0是不可能的。我怎样才能在else子句中赶上这个错误。因此，如果y = 0 "ELSE 0"被激活。

Answer 1

也许还有一个条件？

CASE 
   WHEN sum(y)=0 then 0
   WHEN (1+sum(x)/sum(y)) >=0 and (1+sum(x)/sum(y)) < 0.5 Then 1 
   ELSE 0
END

Answer 2

尝试使用表达式NullIf(sum(y), 0)代替sum(y)：

select
    CASE
        WHEN (1+sum(x)/NullIf(sum(y), 0)) >=0
         and (1+sum(x)/NullIf(sum(y), 0)) < 0.5 Then 1
        ELSE 0
    END

SQLFiddle示例

Answer 3

case when
              sum(coalesce(y, 0)) <> 0 
              and (1+sum(x)/sum(coalesce(y, 0))) >= 0 
              and (1+sum(x)/sum(coalesce(y, 0))) < 0.5 then 
   1 
else
   0
end

Answer 4

您需要先检查分母是否为零如果是，那么不要计算公式返回零其他计算公式

在代码中：

CASE WHEN (1+sum(x)/sum(y)) >=0 and (1+sum(x)/sum(y)) < 0.5 Then 1
ELSE 0

将其修改为：

CASE
WHEN SUM(isnull(y,0))=0 then 0
ELSE
  CASE
     WHEN (1+sum(x)/sum(y)) >=0 and (1+sum(x)/sum(y)) < 0.5
     THEN 1
  END
END AS [RESULT]

在'when else'环境中进行0划分

4 个答案: