Question

我正在使用AFNetworking解析一些json并且非常喜欢它。

现在我想更深入了解。我的json输出看起来像这样

-result
  -0
    rezept_id : value1
    rezept_name : value2
    rezept_zubereitung : value3

在此之前一切正常，我可以解析价值。但现在它继续像这样

-rezept_bilder
  -0    
    -bigfix

      file : value4
      file_path : value5

现在我要解析json属性文件值（value4）并将其显示在图像视图中。要显示图像，如果它在主图像上，我会做这样的事情。

[self.restuarantImageView setImageWithURL:[NSURL URLWithString:[self.restuarantDetail objectForKey:@"file"]]];

但是我如何告诉他文件值不是在主要文件上，而是在

下

-rezept_bilder
 -0
  - bigfix

这是我用来解析数据的代码，我被卡住了。

-(void)makeRestuarantsRequests3{


    NSURL *url = [NSURL URLWithString:@"http://api.chefkoch.de/api/1.0/api-recipe.php?    zufall=1&divisor=0&limit=1"];

   NSURLRequest *request = [NSURLRequest requestWithURL:url];

AFJSONRequestOperation *operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:request
                                                                                    success:^(NSURLRequest *request, NSHTTPURLResponse *response, id responseObject) {
                                                                                        self.googlePlacesArrayFromAFNetworking3 = [responseObject objectForKey:@"result"];
                                                                                        NSDictionary *tempDictionary3= [self.googlePlacesArrayFromAFNetworking3 objectAtIndex:0];
                                                                                      self.zubereitung.text = [tempDictionary3 objectForKey:@"rezept_zubereitung"];
                                                                                             self.Name.text = [tempDictionary3 objectForKey:@"rezept_name"];


                                                                                    }
                                                                                    failure:^(NSURLRequest *request, NSHTTPURLResponse *response, NSError *error, id responseObject) {
                                                                                        NSLog(@"Request Failed with Error: %@, %@", error, error.userInfo);


                                                                                    }];

提前致谢并抱歉我的英文不好，希望你们明白我的问题所在！

----------- EDIT

感谢现在的工作：D

你真的医治了我

这就是我做的方式

-(void)makeRestuarantsRequests3{


NSURL *url = [NSURL URLWithString:@"http://api.chefkoch.de/api/1.0/api-recipe.php?zufall=1&divisor=0&limit=1"];

   NSURLRequest *request = [NSURLRequest requestWithURL:url];

AFJSONRequestOperation *operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:request
                                                                                    success:^(NSURLRequest *request, NSHTTPURLResponse *response, id responseObject) {
                                                                                        self.googlePlacesArrayFromAFNetworking3 = [responseObject objectForKey:@"result"];
                                                                                        NSDictionary *tempDictionary3= [self.googlePlacesArrayFromAFNetworking3 objectAtIndex:0];
                                                                                      self.zubereitung.text = [tempDictionary3 objectForKey:@"rezept_zubereitung"];
                                                                                             self.Name.text = [tempDictionary3 objectForKey:@"rezept_name"];


                                                                                        self.googlePlacesArrayFromAFNetworking5 =[tempDictionary3 objectForKey:@"rezept_bilder"];

                                                                                        NSDictionary *tempDictionary4= [self.googlePlacesArrayFromAFNetworking5 objectAtIndex:0];

                                                                                        NSDictionary *tempDictionary5 = [tempDictionary4 objectForKey:@"bigfix"];


                                                                                        [self.Bild setImageWithURL:[NSURL URLWithString:[tempDictionary5 objectForKey:@"file"]]];

Answer 1

尝试改变它，如下所示。如果可能的话，发布responseObject的JSON，以便更清楚地看到。

self.googlePlacesArrayFromAFNetworking3 = [responseObject objectForKey:@"result"];                                                         

NSDictionary *tempDictionary3= [[self.googlePlacesArrayFromAFNetworking3 objectAtIndex:0] obejctForKey:@"bigfix"];

self.zubereitung.text = [tempDictionary3 objectForKey:@"rezept_zubereitung"];                                                                                             
self.Name.text = [tempDictionary3 objectForKey:@"rezept_name"];

AFNetworking更深入地解析json

1 个答案: