PHP - 从单个mysql表中检索多个记录并附加到字符串

Question

我在mysql中有以下表格。我需要从该表中选择Hid（s）并将结果附加到字符串'$ s'。如果你可以帮忙的话会很棒。

表名：CASES

Did   Hid   Year  Case
---   ---   ----  ----
 1     1    2011   6
 1     1    2012   7
 2     2    2011   40
 2     2    2012   10

php代码段：

$did=1;
$yr=2011;
$s='';
$q="select Hid from CASES where Did=$did and Year=$yr and Case!=0 ";
$r=mysql_query($q);
while($rw=mysql_fetch_assoc($r))
{
    //I need to append the Hid(s) to a String '$s' declared above
}

Answer 1

假设您的查询有效，看起来可能是：

$did=1;
$yr=2011;
$s='';
$q="select Hid from CASES where Did=$did and Year=$yr and Case!=0 ";
$r=mysql_query($q);
while($rw=mysql_fetch_assoc($r))
{
    $s .= $rw['Hid'];
}

这只会给你一个包含所有Hids的字符串..如果你想在中间或其他地方有一个角色，你可以：

$did=1;
$yr=2011;
$s=array();
$q="select Hid from CASES where Did=$did and Year=$yr and Case!=0 ";
$r=mysql_query($q);
while($rw=mysql_fetch_assoc($r))
{
    $s[] = $rw['Hid'];
}
$result = implode( ',', $s );

上面的

$ result将以逗号分隔的Hids列表结束。

Answer 2

使用string concatenation operator：

$s .= $rw['Hid'];

Answer 3

获取/检索数据到数组并将其内嵌到字符串中。参考 http://php.net/manual/en/function.implode.php

for implode

Answer 4

$did=1;
$yr=2011;
$s='';
$q="select Hid from CASES where Did=$did and Year=$yr and Case!=0 ";

    $r=mysql_query($q);
    while($rw=mysql_fetch_assoc($r))
    {
        $s .= $rw['hid'] . '<br />';
    }



echo $s;