HttpClient 4.2.5。如何重新发送Get请求？

Question

我使用apache HTTP客户端API在Java中编写了我的客户端程序。我想要做的是向服务器发送请求。如果发送的请求的响应代码不是200，那么我必须向服务器重新发送请求。这样做时我收到以下错误。

    java.lang.IllegalStateException: Invalid use of BasicClientConnManager: connection still allocated.
Make sure to release the connection before allocating another one.
    at org.apache.http.impl.conn.BasicClientConnectionManager.getConnection(BasicClientConnectionManager.java:162)
    at org.apache.http.impl.conn.BasicClientConnectionManager$1.getConnection(BasicClientConnectionManager.java:139)
    at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:456)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:906)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:805)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:784)
    at main.ApacheGet.sendGet(ApacheGet.java:31)
    at main.ApacheGet.main(ApacheGet.java:17)

我正在努力实现LongPolling。当我收到回复时，我发送了一个新请求。如果我收到200以外的响应代码，我会发送一个新请求。我明白这个错误意味着什么，但我不知道如何克服它。以下是我的代码。

    private void sendGet() throws Exception {
            HttpClient client = new DefaultHttpClient();
            HttpGet request = new HttpGet(
                    "http://localhost:8080/MyServlet/Servlet?id=1001");
            System.out.println("Started");
            HttpResponse response;
            while (true) {
                System.out.print("looped back");
                response = client.execute(request);
                int status = response.getStatusLine().getStatusCode();
                System.out.println("Got the response. Status code:" + status);
                if (status == 200) {
                    StringBuffer textview = new StringBuffer();
                    // Get the response
                    BufferedReader rd = new BufferedReader(new InputStreamReader(
                            response.getEntity().getContent()));
                    String line = "";
                    while ((line = rd.readLine()) != null) {
                        textview.append(line);
                    }
                    System.out.print(textview.toString());
                }
                else{
                    continue;
                }
            }
     }

提前致谢:)。