Question

我的收藏就像

{queid:'1',date:'07023/2013',topic: 'topic1'}
{queid:'2',date:'07022/2013',topic: 'topic2'}
{queid:'3',date:'07022/2013',topic: 'topic1'}
{queid:'4',date:'07023/2013',topic: 'topic1'}

我希望我的输出像

{topic1:
    [ {date:'07/23/2013',count:2},
      {date:'07/22/2013',count:1}
    ]
}

这可以做到mongodb ..

我试过这个

que.aggregate([{$match:c},{$group:{_id:'$topic',count:{$push:'$date'}}}])

，输出为

{
        "_id" : "topic",
        "count" : [
                "2013-06-04",
                "2013-06-06",
                "2013-06-17",
                "2013-06-20"
] }

我能够理解如何对数组进行分组并填充计数。

Answer 1

我不知道代码中的{$match:c}是什么意思。实际上，我是mongodb的新手，这段代码：

que.aggregate([
  {$group:{_id:{"topic":"$topic","date":"$date"}, sum:{$sum:1}}},
  {$group:{_id:"$_id.topic", "dates":{$push:{"date":"$_id.date", "count":"$sum"}} }}
])

产生

{
  "result" : [
     {
      "_id" : "topic2",
      "dates" : [
        { "date" : "07022/2013", "count" : 1}
      ]
     },
     {
      "_id" : "topic1",
      "dates" : [
        { "date" : "07022/2013", "count" : 1},
        { "date" : "07023/2013", "count" : 2}
      ]
     }
  ],
  "ok" : 1
}

我认为你可以玩它来得到你想要的东西。

Answer 2

Map-Reduce可能适合你。

例如：

map = function (){
  emit(this.topic+this.date, 1);
}

reduce = function (id, vals){
  return Array.sum(vals);
}

db.coll.mapReduce(map, reduce, {out:'results'});

http://docs.mongodb.org/manual/tutorial/map-reduce-examples/

mongodb聚合框架由多个字段组成

2 个答案: