假设我们有一个SVG转换字符串:
transform = "translate(6,5),scale(3,3)";
我们可以使用一个灵活的正则表达式函数将其解析成可用的东西吗?
答案 0 :(得分:14)
这里有一段很棒的代码片段,可以为您提供所需的代码,如果您打算解析的字符串具有不同数量的参数,它应涵盖大多数情况:
function parse (a)
{
var b={};
for (var i in a = a.match(/(\w+\((\-?\d+\.?\d*e?\-?\d*,?)+\))+/g))
{
var c = a[i].match(/[\w\.\-]+/g);
b[c.shift()] = c;
}
return b;
}
运行此
parse('translate(6,5),scale(3,3.5),a(1,1),b(2,23,-34),c(300)');
会导致这个:
{
translate: [ '6', '5' ],
scale: [ '3', '3.5' ],
a: [ '1', '1' ],
b: [ '2', '23', '-34' ],
c: [ '300' ]
}
答案 1 :(得分:4)
假设您在浏览器中运行,您还可以使用SVG DOM来解析和解码转换字符串。
var svgns = "http://www.w3.org/2000/svg";
function getTransformList(transformStr)
{
// Create a fake <rect> element to set the transform to
var rect = document.createElementNS(svgns, "rect");
rect.setAttribute("transform", transformStr);
// Use the DOM to get the list of decoded transforms
dumpTransform(rect.transform.baseVal);
}
function dumpTransform(transformList)
{
for (var i=0; i<transformList.length; i++)
{
var transform = transformList[i];
var m = transform.matrix;
switch (transform.type)
{
case 2:
console.log("translate("+m.e+","+m.f+")");
break;
case 3:
console.log("scale("+m.a+","+m.d+")");
break;
case 4:
console.log("rotate("+transform.angle+")");
// TODO need to also handle rotate(angle, x, y) form
break;
case 5:
// TODO skewX()
break;
case 6:
// TODO skewY(()
break;
case 1:
default:
console.log("matrix("+m.a+","+m.b+","+m.c+","+m.d+","+m.e+","+m.f+")");
break;
}
}
}
getTransformList("translate(6,5),scale(3,3)");
&#13;
答案 2 :(得分:3)
var transform = "translate(6,5),scale(3,3)";
var translate = /translate\(\s*([^\s,)]+)[ ,]([^\s,)]+)/.exec(transform);
var translateX = translate[1]
var translateY = translate[2]
var scale = /scale\(\s*([^\s,)]+)[ ,]([^\s,)]+)/.exec(transform);
var scaleX = translate[1]
var scaleY = translate[2]
transformValues = {translate:{x:translateX,y:translateY},
scale:{x:scaleX,y:scaleY}}
非常粗暴,但@icedwater让我自己完成所有工作......
答案 3 :(得分:3)
改编自@ chernjie的解决方案:
function parse_transform(a) {
var b = {};
for (var i in a = a.match(/(\w+)\(([^,)]+),?([^)]+)?\)/gi)) {
var c = a[i].match(/[\w\.\-]+/g);
b[c.shift()] = c;
}
return b;
}
答案 4 :(得分:1)
我将对此进行一次尝试,并表示您希望将其解析为包含每个属性作为列表中条目的JSON对象。这是我到目前为止最接近的:
function listIntoJSON(theTransformInQuestion) {
// let's work with transform = "translate(6,5),scale(3,3)" as specified.
var result = []; // empty list to be returned
var splitList = theTransformInQuestion.split(/\W/);
// now splitList is ["translate", "6", "5", "", "scale", "3", "3", ""]
for (var t = 0; t < splitList.length; t += 4) {
var op = {};
op.name = splitList[t];
op.x = splitList[t + 1];
op.y = splitList[t + 2];
result.push(op); // add op to the result list
}
return result;
}
将采取
transform = "translate(6,5),scale(3,3)";
并返回
[
{name: "translate", x: "6", y: "5"},
{name: "scale", x: "3", y: "3"}
]
并且应该适用于任意数量的转换。一点点黑客,但它现在会做。
答案 5 :(得分:0)
即使是一个老问题,今天我也有同样的需求,并最终得到了这个正则表达式:
const regex = /((\w+)\((,?\s*-?\d*\.?\d+(px|in|px|cm|mm|pt|pc|em|ex|ch|rem|deg|rad|grad|turn)?)+\)\s*)/gi;
很长,但是它也考虑了度量单位。
您可以在这里进行测试:https://regex101.com/r/M8rRjo/1/