Question

我有一些lua脚本，有一些长时间运行的任务，比如获取一个网页，所以我让它产生然后C代码句柄获取页面作业异步，所以线程可以自由地做其他工作，并在指定时间后检查回来看看是否已完成获取页面作业，如果是，则恢复脚本。问题是异步等待后线程无法恢复作业。这是我的代码，我从课堂上把它拉了下来，所以有点混乱对不起


////script:
 function Loginmegaupload_com(hp, user, pass, cookie)
    setURL(hp, "http://megaupload.com/?c=login")
    importPost(hp, "login=1&redir=1")
    addPost(hp, "username", user)
    addPost(hp, "password", pass)
    GetPage()
    if isHeaderContain(hp, "user=") ~= nil then
        SetFileLink(cookie, GetAllCookie(hp))
        return 1
    else
        return 0
    end
end
////c code
int FileSharingService::GetPage(lua_State *ls)
{
    return lua_yield(ls, 0);
}

void FileSharingService::AsyncWait(Http_RequestEx *Http, lua_State *LS, boost::asio::deadline_timer* Timer)
{
    if( (Http->status_code == Http_RequestEx::ERROR) || (Http->status_code == Http_RequestEx::FISNISHED))
    {
        if(Http->status_code == Http_RequestEx::FISNISHED)
        {
            int result = lua_resume(LS, 0); // here I got result  == 2 mean error ?
            if(result  == 0)//lua script exit normal, resume success
            {
                delete Http;
                delete Timer;
            }
        }
        else
            return;
    }
    else
    {
        Timer->expires_from_now(boost::posix_time::milliseconds(200));
        Timer->async_wait(boost::bind(&FileSharingService::AsyncWait, this, Http, LS, Timer));
    }
}



bool FileSharingService::Login(string URL, string User, string Pass, string &Cookie)
{
    Http_RequestEx *http = new Http_RequestEx;
    http->url = URL;
    LuaWarper* Lua = Lua_map[boost::this_thread::get_id()];  //one main luaState per ioservice thread
    lua_State *thread = lua_newthread(Lua->GetState());

    boost::asio::deadline_timer *timer = new boost::asio::deadline_timer(*HClient.ioservice);

    string functioname = "Login" + GetServicename(URL);
    if( Lua->isFunctionAvaliable(functioname.c_str()) == false )
    {
        throw(FileSharingService::SERVICE_NOT_AVALIABLE);
    }
    else
    {
        lua_getglobal(thread, functioname.c_str());
        lua_pushlightuserdata(thread, http);
        lua_pushstring(thread, User.c_str());
        lua_pushstring(thread, Pass.c_str());
        lua_pushlightuserdata(thread, &Cookie);
        int result = lua_resume(thread, 4);
        if(result == LUA_YIELD)
        {
            HClient.Do(*http, false);
            AsyncWait(http, thread, timer);
        }
        else if(result == 0)
        {
            //fisnished at first call
        }
        else
        {
            //yield error, will handle late
        }
    }
}

Answer 1

抱歉没关系这个问题，lua_resume返回2个意思错误，但脚本工作正常，asio让页面工作正常，我跟踪了对lua_resume失败做出响应的行：

httpinfo.header.append(buffer, (HeaderEndIndex-buffer+2) );

如果我评论该行lua_resume按预期工作则返回0均值脚本退出，此行不做任何可能影响lua线程状态的事情它只是一个字符串赋值，我检查没有溢出。太奇怪了。

async_wait之后不能lua_resume？

1 个答案: