爵士,, 我想通过在下面输入以下链接来尝试我的应用程序来测试推送通知,但它是尝试,没有任何影响。请您告诉我测试我的应用程序的超链接的正确格式是什么?
以下是我的链接
https://android.googleapis.com/gcm/send?registration_ids=
APA91bHhJQJGK1OJxYHcZeH81JoAprU97CAvMHQ58cHj3MYHD204MTn1W9Kl_i51UV8ej5qwLfkwvK-vihfuWjXG6iBvkUZJuclqoNbAjx_K2mN_P2ai4rI82P0dax_tm7NHc-k_1FsBn6hvwxjxxPdgMdtYpSIdwA
&data.message="hello testing"
collapse_key = score_update& time_to_live = 108& delay_while_idle = 1& data.message =“+ value +”
答案 0 :(得分:1)
您实际上可以从Android设备本身进行测试:
public class PushTester {
final static private String deviceId = "YOUR_DEVICE_ID";
final static private String apiId = "YOUR_API_ID";
final static private String sendUrl = "https://android.googleapis.com/gcm/send";
static void testPush() {
URL url;
HttpsURLConnection urlConnection;
OutputStream os = null;
InputStream is = null;;
try {
url = new URL(sendUrl);
urlConnection = (HttpsURLConnection) url.openConnection();
urlConnection.setUseCaches(false);
urlConnection.setConnectTimeout(3000);
urlConnection.setReadTimeout(3000);
urlConnection.setRequestMethod("POST");
urlConnection.setRequestProperty("User-Agent", "Android Push tester");
urlConnection.setRequestProperty("Content-Type", "application/json");
urlConnection.setRequestProperty("Authorization", "key="+apiId);
JSONObject message = new JSONObject();
JSONArray regIds = new JSONArray();
JSONObject data = new JSONObject();
regIds.put(deviceId);
message.put("registration_ids", regIds);
//message.put("collapse_key", value)
data.put("something", "value");
message.put("data", data);
urlConnection.setDoOutput(true);
os = urlConnection.getOutputStream();
os.write(message.toString().getBytes());
os.flush();
int status = urlConnection.getResponseCode();
is = urlConnection.getInputStream();
byte[] response = new byte[4096];
is.read(response);
String responseText = String.valueOf(response);
} catch (MalformedURLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (ProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
finally {
try {
if (os != null) {
os.close();
}
if (is != null) {
is.close();
}
}
catch (Exception ex) {
ex.printStackTrace();
}
os = null;
is = null;
}
}
}