Question

我需要从sqlserver2008r2获取记录，我查询当前周的记录是：

select EmpCode,EventDate1 as EventDate,InTime,
case when OutTime is null then 'N/A' else Outtime end as OutTime from    
TMS_HOURCALC WHERE intime1
  BETWEEN dateadd(dd,(datediff(DD,-53684,getdate())/7)*7,-53684) 
    AND dateadd(dd,((datediff(dd,-53684,getdate())/7)*7)+7,-53684) 
    and empcode = @empcode
GROUP BY EmpCode, InTime,OutTime, EventDate1,intime1     
order by intime1;

任何人都可以帮助我从上周日到上周六获取上周的记录。

Answer 1

对列进行计算并在where子句中引用它将会产生糟糕的性能。这是一个更好的方法：

select EmpCode,EventDate1 as EventDate,InTime,
case when OutTime is null then 'N/A' else Outtime end as OutTime from    
TMS_HOURCALC 
WHERE intime1 >= dateadd(dd,(datediff(DD,-1,getdate())/7)*7-7,-1) 
and intime1 < dateadd(dd,((datediff(dd,-1,getdate())/7)*7),-1) 
and empcode = @empcode
GROUP BY EmpCode, InTime,OutTime, EventDate1,intime1     
order by intime1;

Answer 2

确保您的数据库@@DateFirst设置为7（星期日默认值）并使用DATEPART()

尝试使用：

where 
DATEPART(ww, intime1) = DATEPART(ww, GetDate())
and 
YEAR(intime1) = YEAR(GetDate())

如何编写查询来获取上周的记录

2 个答案: