我是hibernate的新手。我要表部门和老师。一个部门可以有很多教师,但一个教师只能隶属于一个部门。我有以下映射:
@Entity
@Table(name = "department")
public class Department {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Integer id;
@Column(name = "name")
private String name;
@Column(name = "description")
private String description;
@OneToMany (cascade=CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name = "department_id")
private List<Teacher> teachers = new ArrayList<Teacher>();
}
和
@Entity
@Table(name = "teacher")
public class Teacher {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Integer id;
@Column(name = "fName")
private String fName;
@Column(name = "lName")
private String sName;
@Column(name = "degree")
private String degree;
@ManyToOne
private Department department;
}
还有getter和setter,为简单起见,我省略了它们。 我正在使用MySql数据库。当我试图用新老师插入新部门时,一切正常。但是,我也希望能够获得一个完整的教师部门列表,分配给每个部门。目前在我的数据库中我有5个部门和13个 老师。但是当我执行以下代码时:
DepartmentDaoImpl ddi = new DepartmentDaoImpl();
List<Department> departments = ddi.getAllDepartment();
for (Department k : departments){
printDepartmentData(k);
List<Teacher> teachers = k.getTeachers();
for (Teacher t : teachers){
printTeacherName(t);
}
}
我的getAllDepartments实现:
@Override
public ArrayList getAllDepartment() throws SQLException {
Session session = null;
ArrayList<Department> result = null;
try{
session = HibernateUtil.getSessionFactory().openSession();
result = (ArrayList)session.createCriteria(Department.class).list();
}catch(Exception ex){
ex.printStackTrace();
}finally{
if(session != null && session.isOpen()){
session.close();
}
}
return result;
}
创建表的SQL:
CREATE TABLE teacher (
id INTEGER PRIMARY KEY auto_increment,
fName varchar(30),
lName VARCHAR(30),
degree VARCHAR(100),
department_id INTEGER
);
CREATE TABLE department(
id INTEGER PRIMARY KEY auto_increment,
name VARCHAR(100),
description VARCHAR(5000)
);
我得到了13个部门的实例。我得到了第一个部门的5个实例(我有5个教师分配给它)每个人都分配了相同的五个教师,第二个部门的两个实例(我有两个教师分配给它)每个部门都有两个相同的教师分配,所以上。 有人可以弄清楚,如何解决它?我需要获得5个部门实例,用 相应的教师人数。
答案 0 :(得分:3)
由于您使用fetch = FetchType.EAGER
配置了一对多关系,因此hibernate会对两个表执行连接。您看到的结果是由此连接引起的。
确保equals()
和hashCode()
中的Department
和Teacher
方法都正确无误。如果这不能解决问题,请尝试使用Set
代替List
。
答案 1 :(得分:0)
进行以下更改并进行测试
@OneToMany (cascade=CascadeType.ALL, fetch = FetchType.EAGER, mappedBy="department")
private List<Teacher> teachers = new ArrayList<Teacher>();
答案 2 :(得分:0)
尝试改变这个:
@OneToMany (mappedBy="department", cascade=CascadeType.ALL, fetch = FetchType.EAGER)
private Set<Teacher> teachers = new HashSet<Teacher>();
并改变:
@ManyToOne
private Department department;
到:
@Collumn(name = "department")
private Integer department;
答案 3 :(得分:0)
只需在你的dao中尝试这个,它会有帮助
result =(ArrayList)session.createCriteria(Department.class)。 setResultTransformer(Criteria.DISTINCT_ROOT_ENTITY).list();