Question

我在MySql中有一个MonthlySubscriber表：

CREATE TABLE  MonthlySubscriber (
 MobileNo varchar(20) NOT NULL,
 Month int(11) NOT NULL,
 PRIMARY KEY (MobileNo, Month)
 );

一个手机不能在一个多月内多次来。所以根据手机，我不得不加入我的桌子。

需求量的：

我想自己加入我的桌子，只想要第一张桌子的MobileNo和Month以及第二张桌子的月份。我希望（所有mobileNo和Month的数量从第一个表和月份从第二个表）的顺序和组来自列（月份从第一个表和月份从第二个表）

我的MySql查询：

 Select COUNT(t.MSI), t.Mon1 ,t.Mon2 from
 ( SELECT
     MonthlySubscriber.MobileNo as MSI,
     MonthlySubscriber.Month as Mon1,
     MonthlySubscriber.Month as Mon2
   FROM MonthlySubscriber as MonthlySubscriber
   LEFT JOIN MonthlySubscriber as MonthlySubscriber on
         (MonthlySubscriber.MobileNo = MonthlySubscriber.MobileNo )
   ORDER by MonthlySubscriber.Month
 )
 t GROUP BY t.Mon1, t.Mon2;

我想在Hibernate条件查询中完全相同的查询。

实施例

表

> MobileNo  || Month 
> 852335421 || 1 
> 852335421 || 2 
> 852335421 || 5
> 994534554 || 3 
> 924443443 || 4 
> 994534554 || 7
> 864645353 || 1
result should come like this
>count_of_mobileNos || month 1 || month 2
>   2               ||  1       || 1
>   1               ||  1       || 2
>   1               ||  1       || 5
>   1               ||  2       || 2
>   1               ||  2       || 5
>   1               ||  3       || 3
>   1               ||  3       || 7
>   1               ||  4       || 4
>   1               ||  5       || 5
>   1               ||  7       || 7

注意月份是1-12的整数

Answer 1

试试这个：

SELECT count(MobileNo),
count( case when m.Month=1 then m.Month else 0 end ) as Month 1,
count( case when m.Month=2 then m.Month else 0 end ) as Month 2,
count( case when m.Month=3 then m.Month else 0 end ) as Month 3,
.
.
.
count( case when m.Month=12 then m.Month else 0 end ) as Month 12
FROM MonthlySubscriber m
GROUP BY m.Month

hibernate条件查询自联接并获取特定列和计数限制

1 个答案: