我在相关帖子上学到了how to send additional parameters to a thread,但现在我想知道我是否可以将数据(由线程处理)恢复回调用函数!
我正在编写一个程序,我需要使用一个不断将用户输入放入字符串变量的线程。问题是我不知道如何将字符串变量数据返回到main()显示(图形)。所以(我更喜欢)获取用户输入和字符串显示是独立完成的(因为它们需要以不同的速率循环:比如......用户输入为30 fps,显示为16 fps)
我希望我很清楚
这是一个理想的问题情况(但不是我需要解决的问题):
typedef struct
{
int a,b;
}ThreadData;
int avg(void* data)
{
ThreadData* tdata=(ThreadData*)data;
int processed_average=(tdata->a+tdata->b)/2.0;
//this is what i want to send back to the main()
return 0;
}
void main()
{
int a=10,b=20;
SDL_Thread* mythread=SDL_CreateThread(avg,myThreadData);
cout<<"The average of a and b is "; //i dont know what to put here!
}
请原谅我演示
中的语法错误作为结论性问题:
如何获取由线程(使用循环)不断更新的字符串的当前内容返回main(),其中包含另一个循环,该循环使用当前(图形)连续更新屏幕(最新) )字符串的内容?
答案 0 :(得分:2)
线程间通信的一个合适模式是消息队列 - 您可以使用互斥锁,列表和条件变量实现一个 - 一个使用现成的变体。以下是您可以查看的一些实现:
然后,您可以将线程数据推送到队列中 - 以及队列中的主要pop数据。
编辑1:响应OP的编辑。
如果你有一个必须由线程编辑然后由main渲染的字符串,最好只使用std :: string,用互斥锁保护对它的所有访问,然后使用条件变量来发信号字符串更改时的主线程。将在一分钟内尝试为您编写一些示例代码。
编辑2:承诺的示例代码:
#include <SDL/SDL.h>
#include <SDL/SDL_thread.h>
#include <iostream>
#include <sstream>
#include <stdexcept>
class SdlMutex
{
public:
SdlMutex()
{
mutex = SDL_CreateMutex();
if ( !mutex ) throw std::runtime_error( "SDL_CreateMutex == NULL" );
}
~SdlMutex()
{
SDL_DestroyMutex( mutex );
}
void lock()
{
if( SDL_mutexP( mutex ) == -1 ) throw std::runtime_error( "SDL_mutexP == -1" );
// Note:
// -1 does not mean it was already locked - it means there was an error in locking -
// if it was locked it will just block - see SDL_mutexP(3)
}
void unlock()
{
if ( SDL_mutexV( mutex ) == -1 ) throw std::runtime_error( "SDL_mutexV == -1" );
}
SDL_mutex* underlying()
{
return mutex;
}
private:
SDL_mutex* mutex;
};
class SdlScopedLock
{
public:
SdlScopedLock( SdlMutex& mutex )
:
mutex( mutex )
{
mutex.lock();
}
~SdlScopedLock()
{
try
{
this->unlock();
}
catch( const std::exception& e )
{
// Destructors should never throw ...
std::cerr << "SdlScopedLock::~SdlScopedLock - caught : " << e.what() << std::endl;
}
}
void unlock()
{
mutex.unlock();
}
private:
SdlMutex& mutex;
};
class ThreadData
{
public:
ThreadData()
:
dataReady( false ),
done( false )
{
condition = SDL_CreateCond();
}
~ThreadData()
{
SDL_DestroyCond( condition );
}
// Using stringstream so I can just shift on integers...
std::stringstream data;
bool dataReady;
bool done;
SdlMutex mutex;
SDL_cond* condition;
};
int threadFunction( void* data )
{
try
{
ThreadData* threadData = static_cast< ThreadData* >( data );
for ( size_t i = 0; i < 100; i++ )
{
{
SdlScopedLock lock( threadData->mutex );
// Everything in this scope is now syncronized with the mutex
if ( i != 0 ) threadData->data << ", ";
threadData->data << i;
threadData->dataReady = true;
} // threadData->mutex is automatically unlocked here
// Its important to note that condition should be signaled after mutex is unlocked
if ( SDL_CondSignal( threadData->condition ) == -1 ) throw std::runtime_error( "Failed to signal" );
}
{
SdlScopedLock lock( threadData->mutex );
threadData->done = true;
}
if ( SDL_CondSignal( threadData->condition ) == -1 ) throw std::runtime_error( "Failed to signal" );
return 0;
}
catch( const std::exception& e )
{
std::cerr << "Caught : " << e.what() << std::endl;
return 1;
}
}
int main()
{
ThreadData threadData;
SDL_Thread* thread = SDL_CreateThread( threadFunction, &threadData );
while ( true )
{
SdlScopedLock lock( threadData.mutex );
while ( threadData.dataReady == false && threadData.done == false )
{
// NOTE: must call condition wait with mutex already locked
if ( SDL_CondWait( threadData.condition, threadData.mutex.underlying() ) == -1 ) throw std::runtime_error( "Failed to wait" );
}
// once dataReady == true or threadData.done == true we get here
std::cout << "Got data = " << threadData.data.str() << std::endl;
threadData.data.str( "" );
threadData.dataReady = false;
if ( threadData.done )
{
std::cout << "child done - ending" << std::endl;
break;
}
}
int status = 99;
SDL_WaitThread( thread, &status );
std::cerr << "Thread completed with : " << status << std::endl;
}
编辑3:然后笼子落下......
你可能不应该在C ++中使用SDL线程支持,或者至少将它包装在某些RAII类中 - 例如,在上面的代码中 - 如果抛出异常 - 你应该确保mutex被解锁。我将使用RAII更新示例,但SDL线程助手有许多更好的选择。 (注意:编辑4添加RAII - 所以现在当抛出异常时互斥锁被解锁)
编辑4:代码现在更安全 - 仍然确保你做错误检查 - 基本上:不要在C ++中使用SDL线程 - 使用boost :: thread或std :: thread。
答案 1 :(得分:1)
我想你想要SDL_WaitThread。
void SDL_WaitThread(SDL_Thread *thread, int *status);
线程函数的返回码放在指向的区域中 状态,如果状态不是
NULL
。
让avg
函数返回平均值。