我在下面重复了这个代码,我假设这可以合并但是如果你注意到每个字典都是不同的通用字典:
dictionary1的类型为
Dictionary<int, ContinuousIntegrationSolution>
而词典2的类型为:
Dictionary<int, BugTracker>
DataTable dt = GetDataTable("CI");
for (int i = 0; i < dt.Rows.Count; i++)
{
DataRow dr = dt.Rows[i];
int id = Convert.ToInt32(dr["id"]);
string name = dr["name"].ToString();
_dictionary1[id] = new ContinuousIntegrationSolution(){Name = name};
}
DataTable dt1 = GetDataTable("Bug_Tracking");
for (int i = 0; i < dt1.Rows.Count; i++)
{
DataRow dr = dt1.Rows[i];
int id = Convert.ToInt32(dr["id"]);
string name = dr["name"].ToString();
_dictionary2[id] = new BugTracker() { Name = name };
}
DataTable dt2 = GetDataTable("SDLC");
for (int i = 0; i < dt2.Rows.Count; i++)
{
DataRow dr = dt2.Rows[i];
int id = Convert.ToInt32(dr["id"]);
string name = dr["name"].ToString();
_dictionary3[id] = new SDLCProcess() { Name = name };
}
注意:我已修复了下面提到的一些拼写错误。
答案 0 :(得分:13)
public interface INameable
{
string Name {get;set;}
}
public static IDictionary<int, T> ReadTable<T>(string tableName)
where T : INameable, new()
{
DataTable dt = GetDataTable(tableName);
var dictionary = new Dictionary<int, T>();
for (int i = 0; i < dt.Rows.Count; i++)
{
DataRow dr = dt.Rows[i];
int id = Convert.ToInt32(dr["id"]);
string name = dr["name"].ToString();
dictionary[id] = new T() { Name = name };
}
return dictionary;
}
如果你有c#4.0动态,你可以避免INameable因某些(轻微)类型安全而丢失
另一种类似于Hakon的回答,但没有暴露字典是
public IDictionary<int,T> ReadTable<T>(
string tableName, Action<T, string> onName)
where T : new()
{
var dictionary = new Dictionary<int,T>();
DataTable table = GetDataTable(tableName);
foreach (DataRow row in table.Rows)
{
int id = Convert.ToInt32(row["id"]);
string name = row["name"].ToString();
var t = new T();
onName(t, name);
dictionary[id] = t;
}
return dictionary;
}
然后像这样消耗:
var ci = ReadTable<ContinuousIntegrationSolution>("CI",
(t, name) => t.Name = name);
var bt = ReadTable<BugTracker >("Bug_Tracking",
(t, name) => t.Name = name);
var sdlc = ReadTable<SDLCProcess>("SDLC",
(t, name) => t.Name = name);
一种替代的,更灵活的方法,但由于类型推断而在呼叫站点使用仍然相当简单:
public IDictionary<int,T> ReadTable<T>(string tableName, Func<string,T> create)
{
DataTable table = GetDataTable(tableName);
var dictionary = new Dictionary<int,T>()
foreach (DataRow row in table.Rows)
{
int id = Convert.ToInt32(row["id"]);
string name = row["name"].ToString();
dictionary[id] = create(name);
}
return dictionary;
}
然后像这样消耗:
var ci = ReadTable("CI",
name => new ContinuousIntegrationSolution() {Name = name});
var bt = ReadTable("Bug_Tracking",
name => new BugTracker() {Name = name});
var sdlc = ReadTable("SDLC",
name => new SDLCProcess() {Name = name});
如果你采用lambda方法,我建议使用后者。
答案 1 :(得分:3)
我不会使用类似于已建议的界面,而是使用lambda函数来执行与此类似的赋值:
public void ReadTable(string tableName, Action<int, string> _setNameAction) {
DataTable table = GetDataTable(tableName);
foreach (DataRow row in table.Rows) {
int id = Convert.ToInt32(row["id"]);
string name = row["name"].ToString();
_setNameAction(id, name);
}
}
并调用这样的方法:
ReadTable("CI", (id, name)
=> _dictionary1[id] = new ContinuousIntegrationSolution{Name = name});
ReadTable("Bug_Tracking", (id, name)
=> _dictionary2[id] = new BugTracker { Name = name });
ReadTable("SDLC", (id, name)
=> _dictionary3[id] = new SDLCProcess { Name = name });
答案 2 :(得分:0)
将它放在具有工厂方法的函数中以实例化id对象。像这样......
public delegate T CreateObjectDelegate<T>(string name);
public static void ProcessDataTable<T>(DataTable dt, Dictionary<int, T> dictionary, CreateObjectDelegate<T> createObj)
{
for (int i = 0; i < dt.Rows.Count; i++)
{
DataRow dr = dt.Rows[i];
int id = Convert.ToInt32(dr["id"]);
string name = dr["name"].ToString();
dictionary[id] = createObj(name);
}
}
static void Main(string[] args)
{
var dt = new DataTable();
var dictionary = new Dictionary<int, BugTracker>();
ProcessDataTable<BugTracker>(dt, dictionary, (name) => { return new BugTracker() { Name = name }; });
}