Question

我有一个包含字符串的二维数组，并希望用它们创建一个LaTeX表。问题是它们可能会更长，并且在15个字符后必须有换行符。

说它是一个2x2数组，包含{{“String11 ....... String11”，“String21”}，{“String12 ....... String12 ....... String12 .. .....“，”String22 ...... String22 ......“}}然后结果看起来像：

\begin{tabular}{cc}
String11.......& String21//
String11       &//
\hline
String12.......&String22......//
String12.......&String22......//
String12.......&  
\end{tabular}

在Java中有这种转换的智能方法吗？

Answer 1

最快捷的方法是在表格的单元格中设置15em文本换行，这可能是您最终要寻找的解决方案：

\begin{tabular}{p{15em} p{15em}}
String11 & String21 \\
\hline
String12 & String22 \\
\end{tabular}

或者，您可能会找到一种方法来制作类似这样的工作：


String11 & String21 \\
\hline
String12 & String22 \\
\end{tabular}

对这个主题进行了一些谷歌搜索，我发现LaTeX表中的

// regex to place a new line delimiter (eg. \newline) after every 15 characters
string11.replaceAll(".{15}", "$0" + someNewLineDelimiter);

并不像我们想要的那样容易，但你应该能找到有用的东西。跨越多行的字符串替代方案似乎是一个糟糕的解决方案。

Answer 2

我不得不承认这个解决方案看起来很难看。我认为有很多语言可以用更少的代码和浮躁来完成这项任务。我怀疑它会在Perl中出现大约10行，或者在J.中出现2行。不过，这是我能想到的最好的行：

import java.util.ArrayList;
import java.util.List;

public class Christian {

   private static final int COLUMNS = 2, CELL_WIDTH = 15;

   private static final String[][] array = {
      {"I have an two dimension array that contains strings and want to create a LaTeX table with them. T",
       "roblem is that they could be longer and there has to be line breakes after 15 characters. Th"},
       {"Say it's a 2x2 array with contains {{'String11.......String11', 'String21'}",
          "{'String12.......String12.......String12.......', 'String22......String22......'}} then the result should look like"}
       };

   public static void main(String[] args) {
      ArrayList<String> lines = new ArrayList<String>();
      lines.add("\\begin{tabular}{cc}");
      for (String[] row : array) {
         lines.addAll(convertRow(row));
         lines.add("\\hline");
      }
      lines.remove(lines.size() - 1);
      lines.add("\\end{tabular}");
      for (String line : lines) {
         System.out.println(line);
      }
   }

   private static List<String> convertRow(String[] row) {
      ArrayList<ArrayList<String>> rearranged = new ArrayList<ArrayList<String>>();
      int deepest = 0;
      for (int col=0; col<row.length; col++) {
         boolean last = (col == row.length - 1);
         String marker = (last) ? "//" : "&";
         String text = row[col];
         ArrayList<String> cell = new ArrayList<String>();
         for (int z=0; z<text.length(); z+=15) {
            String cc = (z+CELL_WIDTH < text.length()) ? text.substring(z, z+CELL_WIDTH) : text.substring(z);
            cell.add(cc + marker);
            deepest = Math.max(deepest, cell.size());
         }
         rearranged.add(cell);
      }
      for (int col=0; col<row.length; col++) {
         ArrayList<String> cell = rearranged.get(col);
         boolean last = (col == row.length - 1);
         String marker = (last) ? "//" : "&";
         while (cell.size() < deepest) cell.add(marker);
      }
      ArrayList<String> lines = new ArrayList<String>();
      for (int line=0; line<deepest; line++) {
         StringBuilder sb = new StringBuilder();
         for (int col=0; col<row.length; col++) {
            sb.append(rearranged.get(col).get(line));
         }
         boolean last = (line == deepest - 1);
         if (last) sb.delete(sb.length() - 2, sb.length());
         lines.add(sb.toString());
      }
      return lines;
   }

}

将Java字符串数组转换为LaTeX表

2 个答案: