我有一个很大的问题。我有我的JSON http://phsjulchsvr4.therock.com.ph:1217/api/users的这个网址,我将使用此代码解析它:
public class JSONParser {
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
// constructor
public JSONParser() {
}
public JSONObject getJSONFromUrl(String url) {
// Making HTTP request
try {
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
}
问题是我无法连接到此URL,因为它具有身份验证。我该怎么办要使用我的JSONParser类连接此URL? HttpResponse可以执行网址
答案 0 :(得分:1)
在执行请求时尝试使用此功能:
try {
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
// Set the username and password
String authStr = "username" + ":" + "password";
// Encode authentication values, and add to header
String authStrEncoded = Base64.encode(authStr.getBytes("UTF-8"));
httpGet.addHeader("Authorization", "Basic " + authStrEncoded);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
答案 1 :(得分:1)
以下是您可能需要的内容:
public String getValueResult(String url) {
System.out.println(url);
String username = "admin";
String password = "admin";
String unp = username+":"+password;
try {
HttpClient httpclient = new DefaultHttpClient();
// HttpPost httppost = new HttpPost(domain.trim()+"/qhms/wse_hmlogin.php?loginid="+user.trim()+"&logpass="+pass.trim());
// HttpPost httppost = new HttpPost(domain+"/qhms/wse_hmlogin.php?loginid="+user+"&logpass="+pass);
// HttpPost httppost = new HttpPost("http://svv.in.net/service/index.php?user=Customer&pass=cus&des=rtr%20r%20rtr%20trtrt");
HttpPost httppost = new HttpPost(url);
// httppost.setHeader( "Authorization","Basic "+"admin:admin");
String encoded_login = Base64.encodeToString(unp.getBytes(), Base64.NO_WRAP);
httppost.setHeader(new BasicHeader("Authorization", "Basic "+encoded_login));
System.out.println("URL="+httppost.toString());
// HttpPost httppost = new HttpPost("http://quantumr.info/qrms/call_service/wse_getitem.php?compkey=astres1312");
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
} catch (Exception e) {
Log.e("log_tag", "Error in http connection" + e.toString());
}
// convert response to string
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
sb = new StringBuilder();
sb.append(reader.readLine() + "\n");
String line = "0";
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result = sb.toString();
} catch (Exception e) {
Log.e("log_tag", "Error converting result " + e.toString());
}
return result;
}