Question

如何在PHP中执行此操作？

我不想只导出csv文件中的表数据并将csv文件存储在备份文件夹中。

为此我正在使用它：

$query = "SELECT * FROM `login_details`";
$file_name = "login_details";
$sql_csv = mysql_query($query) or die("Error: " . mysql_error()); //Replace this line with what is appropriate for your DB abstraction layer

header("Content-type:text/octect-stream");
$done = header("Content-Disposition:attachment;filename=$fileName");

while($row = mysql_fetch_row($sql_csv)) {
     print '"' . stripslashes(implode('","',$row)) . "\"\n";
}

感谢。

Answer 1

你必须打开文件写（句柄）使用http://php.net/manual/en/function.fopen.php

使用创建的句柄来编写字符串http://php.net/manual/en/function.fputcsv.php

完成后关闭句柄（参见doc for fopen）使用fclose（）

例如：

//you code to get data from sql
$handle = fopen('full path to store (you can use ftp etd)', 'w'); // see mode
while($row = mysql_fetch_row($sql_csv)) {
     fputcsv($handle, $row);
}
fclose($handle);

Answer 2

如果您的备份文件夹位于（或可以位于）运行MySql的同一台计算机上，那么实现目标的最快最简单的方法是使用SELECT ... INTO OUTFILE子句

SELECT * 
  FROM login_details
  INTO OUTFILE '/path/to/backup/folder/login_details.csv' 
       FIELDS TERMINATED BY ',' OPTIONALLY ENCLOSED BY '"'
       LINES TERMINATED BY '\n' -- or \r\n

php code

$sql = "SELECT * 
          FROM login_details
          INTO OUTFILE '/path/to/backup/folder/login_details.csv' 
               FIELDS TERMINATED BY ',' OPTIONALLY ENCLOSED BY '\"'
               LINES TERMINATED BY '\n'";
$result = mysql_query($sql);
if (!$result) {
   die('Error: ' . mysql_error()); //TODO better error handling
}

在旁注中：不推荐使用mysql_*扩展名。考虑切换到mysqli或PDO。

Answer 3

您可以使用 fputcsv 来执行此操作。这是功能手册：http://php.net/manual/en/function.fputcsv.php

$query = "SELECT * FROM `login_details`";
$file_name = "login_details";
$sql_csv = mysql_query($query) or die("Error: " . mysql_error()); //Replace this line with what is appropriate for your DB abstraction layer

$fp = fopen('cvsfile.csv', 'w');
while($row = mysql_fetch_row($sql_csv)) {
     fputcsv($fp, split(',', $row));
}
fclose($fp);

以csv格式导出表数据并存储在文件夹中

3 个答案: