我有一个程序可以为评估人员提供技能评级，其标题为“工人”，必须提供他们分配的文件编号。该程序还会引入报告行，每个工作人员都是。
SELECT distinct
o.VP,
o.AVP,
o.Director,
o.Supervisor,
o.Worker,
bs.File_NBR,
s.Skill
bs.score
FROM [New_EEs].[dbo].[SBC_Best_Scores] bs
inner join new_ees.dbo.SBC_Skills s
on bs.Skill_NBR=s.SKILL_NBR
inner join gw_PPP.dbo.Org_Hierarchy oon
bs.File_NBR=o.File_NBR;
我得到的数据集看起来像这样：
VP AVP Director Supervisor Worker File_NBR Skill Rating
Gerald Kris Doris NULL Mack 107812 B2 4
Gerald Kris Doris NULL Mack 107812 D1 3
Gerald Kris Doris NULL Mack 107812 D2 3
Gerald Kris Doris NULL Mack 107812 D3 3
Gerald Kris Doris NULL Mack 107812 E1 4
Gerald Kris Mike NULL Brady 109080 A1 5
Gerald Kris Mike NULL Brady 109080 B1 4
Gerald Kris Mike NULL Brady 109080 B2 3
Gerald Kris Mike NULL Brady 109080 B3 4
Gerald Kris Mike NULL Brady 109080 C1 4
Gerald Kris Mike NULL Brady 109080 C2 4
Gerald Kris Mike NULL Brady 109080 C3 0
Kim Harry NULL Grant Tom 108457 B1 4
Kim Harry NULL Grant Tom 108457 B2 4
Kim Harry NULL Grant Tom 108457 C1 4
Kim Harry NULL Grant Tom 108457 C2: 5
Kim Harry NULL Grant Tom 108457 C5 5
Kim Harry NULL Grant Tom 108457 D1 4
Kim Harry NULL Grant Tom 108457 D2 5
Kim Harry NULL Grant Tom 108457 D3 4
Kim Harry NULL Grant Jean 106934 C5 4
Kim Harry NULL Grant Jean 106934 D1 5
Kim Harry NULL Grant Jean 106934 D3 5
Kim Harry NULL Grant Raphe 108901 B2 5
Kim Harry NULL Grant Raphe 108901 C2 5
Kim Harry NULL Grant Raphe 108901 C3 4
Kim Harry NULL Grant Raphe 108901 C5 5
Kim Harry NULL Grant Raphe 108901 D2 5
Kim Harry NULL Grant Raphe 108901 E1 5
Kim Harry NULL Grant Tyika 107923 B1 5
Kim Harry NULL Grant Tyika 107923 B2 5
Kim Harry NULL Grant Tyika 107923 D2 4
Kim Harry NULL Grant Tyika 107923 D3 4
评级为1到5.我需要做的是创建一个表格，显示按Vp，AVP，主管和主管分组的每项技能的每个评级的计数和百分比。因此，最终属于AVP的所有作品以及最终属于导演等等的所有工作者。
Name Role Skill Count of % of Count of % of
Rating 1 Rating 1 Rating 2 Rating 2
Gerald VP A1 100 29% 130 33%
Gerald VP B1 95 28% 95 24%
Gerald VP B2 120 35% 70 18%
Gerald VP B3 30 9% 100 25%
Kim VP A1
Kim VP B1
Kim VP B2 and so on
Kim VP B3
Kris AVP A1
Kris AVP B1
Kris AVP B2
Kris AVP B3
Harry AVP A1
Harry AVP B1
Harry AVP B2
Harry AVP B3
Doris Director A1
Doris Director B1
Doris Director B2
Doris Director B3
Mike Director A1
Mike Director B1
Mike Director B2
Mike Director B3
Grant Supervisor A1
Grant Supervisor B1
Grant Supervisor B2
Grant Supervisor B3
任何帮助都会很棒！谢谢！
答案 0 :(得分：1)
由于您在不同的列中拥有不同的角色，因此要获得紧凑的查询，您需要动态sql或复杂的数据透视表。因此，我选择了复制和粘贴，因为我认为复杂性不值得你拥有的4个角色。
我已将您的查询T命名为示例。
with roles as (
select VP as Name, 'VP' as Role, Skill, Rating from t where VP is not null
union all
select AVP as Name, 'AVP' as Role, Skill, Rating from t where AVP is not null
union all
select Director as Name, 'Director' as Role, Skill, Rating from t where Director is not null
union all
select Supervisor as Name, 'Supervisor' as Role, Skill, Rating from t where Supervisor is not null
), counts as (
select Name, Role, Skill
,count(case when rating = 1 then 1 else NULL end) as [Count of Rating 1]
,count(case when rating = 2 then 1 else NULL end) as [Count of Rating 2]
,count(case when rating = 3 then 1 else NULL end) as [Count of Rating 3]
,count(case when rating = 4 then 1 else NULL end) as [Count of Rating 4]
,count(case when rating = 5 then 1 else NULL end) as [Count of Rating 5]
,count(*) as TotalCount
from roles
group by Name, Role, skill
)
select Name, Role, Skill
,[Count of Rating 1]
,CONVERT(varchar(10), convert(int,100.0 * [Count of Rating 1]/NULLIF(TotalCount, 0))) + '%' as [% of Rating 1]
,[Count of Rating 2]
,CONVERT(varchar(10), convert(int,100.0 * [Count of Rating 2]/NULLIF(TotalCount, 0))) + '%' as [% of Rating 2]
,[Count of Rating 3]
,CONVERT(varchar(10), convert(int,100.0 * [Count of Rating 3]/NULLIF(TotalCount, 0))) + '%' as [% of Rating 3]
,[Count of Rating 4]
,CONVERT(varchar(10), convert(int,100.0 * [Count of Rating 4]/NULLIF(TotalCount, 0))) + '%' as [% of Rating 4]
,[Count of Rating 5]
,CONVERT(varchar(10), convert(int,100.0 * [Count of Rating 5]/NULLIF(TotalCount, 0))) + '%' as [% of Rating 5]
from counts
order by Name, skill
我在这里做的是将所有角色合并在一起，对角色名称进行硬编码。 roles重新组织表，以便拥有VP的每个人都获得该行的一行，每个拥有AVP的人都获得该行的AVP，.... counts然后计算每个人的所有工人名称，角色和技能。最终选择计算百分比。
这是一个小提琴，展示了它的实际效果：http://sqlfiddle.com/#!3/fe09d/15