Question

我写了一些可怕的代码，但它确实有效。有没有更好的方法来写这个？ _decade.x是NSButtons。

int baseDecade = 1940;
NSString *title;
int currentDecade = 0;

- (IBAction)nameDecade:(id)sender {

    currentDecade = baseDecade;
    title = [NSString stringWithFormat: @"%ld", (long)currentDecade];
    _decade1.stringValue = title;

    currentDecade = currentDecade +10;
    title = [NSString stringWithFormat: @"%ld", (long)currentDecade];
    _decade2.stringValue = title;

    currentDecade = currentDecade +10;
    title = [NSString stringWithFormat: @"%ld", (long)currentDecade];
    _decade3.stringValue = title;

Answer 1

在iOS中，您可以将按钮放在界面构建器中的单个IBOutletCollection中，或者如果您通过代码创建按钮，则可以放在NSArray中。有了这个插座集合/数组，您可以使用循环通过集合中的索引引用_decadeN：

@property (nonatomic, retain) IBOutletCollection(UIButton) NSArray *decadeButtons;
...
for (int i = 0 ; i != decadeButtons.count ; i++) {
    UIButton * decade = decadeButtons[i];
    NSString *title = [NSString stringWithFormat: @"%ld", (long)(baseDecade+10*i)];
    decade.stringValue = title;
}

修改 OSX does not support IBOutletCollections yet，因此您需要将_decadeN按钮置于数组中：

// I am using the new array literal syntax; using arrayWithObjects will work too.
NSArray *decadeButtons = @[_decade1, _decade2, _decade3];
// Use the same loop as above:
for (int i = 0 ; i != decadeButtons.count ; i++) {
    UIButton * decade = decadeButtons[i];
    NSString *title = [NSString stringWithFormat: @"%ld", (long)(baseDecade+10*i)];
    decade.stringValue = title;
}

命名一些NSButtons

1 个答案: