Question

我知道标题不是解释性的，但让我向你解释一下。我正在制作一个Shoutcast流媒体广播项目。当应用程序开始流式传输时，通知栏上会显示一个通知，其中包含无线电名称和当前歌曲ID。到目前为止，一切看起来都很正常，但是当用户触摸通知时（流继续），它再次打开应用程序，另一个流开始播放。我希望我已经很好地解释了这个问题，这里是代码：

编辑：

 Hey again, I have just figured out how to make it that way and here is the sample code.


    String ns = Context.NOTIFICATION_SERVICE;
    mNotificationManager = (NotificationManager) getSystemService(ns);

    icon = R.drawable.rbnot;
    CharSequence tickerText = "Radyo Bilkent";
    long when = System.currentTimeMillis();

    notification = new Notification(icon, tickerText, when);
    notification.flags = Notification.FLAG_ONGOING_EVENT | Notification.FLAG_NO_CLEAR;   
    Intent notificationIntent = new Intent(this, myMain.class);
    notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_SINGLE_TOP);

    Context context = getApplicationContext();
    CharSequence contentTitle = "Radyo Bilkent";
    CharSequence contentText = currPlayView.getText();

    PendingIntent contentIntent = PendingIntent.getActivity(this, 0, notificationIntent, 0);

    notification.setLatestEventInfo(context, contentTitle, contentText, contentIntent);

    mNotificationManager.notify(HELLO_ID, notification);

Answer 1

查看代码。这对我有帮助。

    NotificationManager notificationManager = (NotificationManager) context
            .getSystemService(Context.NOTIFICATION_SERVICE);
    Notification notification = new Notification(icon, message, when);
     Intent notificationIntent = new Intent(context, HomeActivity.class);

    notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP
            | Intent.FLAG_ACTIVITY_SINGLE_TOP);

    PendingIntent intent = PendingIntent.getActivity(context, 0,
            notificationIntent, 0);

    notification.setLatestEventInfo(context, title, message, intent);
    notification.flags |= Notification.FLAG_AUTO_CANCEL;
    notificationManager.notify(0, notification);

Android：点击通知后如何回到同一个应用程序？

1 个答案: