Question

请问您能帮助我再次确定我的代码中的错误吗？每次选择一个案例时，例如你选择了“1”这是“NBA球员”，并且你被问到谁是你最喜欢的球员，一旦你输入你的答案，程序就会结束。我认为问题出在我的getline声明中，但我无法确定它。

#include<iostream>
#include<conio.h>
#include<string>

using namespace std;


int main()
{
  int choice;
  string nbaPlayer;
  string tele;
  string food;
  string subject;
  string x;

  cout << "This program determines your favorites.\n\n";
  cout << "Please select the number of your corresponding choice.";
  cout << "\n1. NBA Player";
  cout << "\n2. Teleserye";
  cout << "\n3. Food";
  cout << "\n4. Subject";
  cout << "\n5. Exit";
  cin >> choice;

  switch (choice)
    {

    case 1:
      cout << "You have chosen NBA Player.\n";
      cout << "Please enter your favorite NBA Player. \n";
      getline(cin, nbaPlayer);
      cout << "Your favorite NBA player is " << nbaPlayer;
      break;

    case 2:
      cout << "You have chosen Teleserye.\n";
      cout << "Please enter your favorite teleserye. \n";
      getline(cin, tele);
      cout << "Your favorite teleserye is " << tele;
      break;

    case 3:
      cout << "You have chosen food.\n";
      cout << "Please enter your favorite food. \n";
      getline(cin, food);
      cout << "Your favorite food is " << food;
      break;

    case 4:
      cout << "You have chosen subject.\n";
      cout << "Please enter your favorite subject. \n";
      getline(cin, subject);
      cout << "Your favorite subject is " << subject;
      break;

    case 5:
      cout << "You chose to exit.\n";
      break;

    default:
      cout <<"\nInvalid input";

    }

  getch();
}

Answer 1

当然它结束了，在switch声明后，没有什么可以继续该程序。

您可能需要围绕输出循环switch：

bool go_on = true;

while (go_on)
{
    // Output menu...
    // Get choice

    switch (choice)
    {
        // All other cases...

    case 5:
        go_on = false;  // Tell loop to end
        break;
    }
}

哦，似乎你的问题是你得到一个空行......这是因为在你得到choice之后，流在输入缓冲区中留下了换行符，所以当你做{{1它会读取换行符而不是您想要的输入。

您可以删除这样的尾随换行符：

std::getline

字符串输入错误

1 个答案: