Question

我知道这已被问了很多，但我似乎找不到合适的答案。在PHPMyAdmin中，用户名“user”和密码“test”存在 - 但由于某种原因，它一直说它没有。代码的输出是：

成功连接到DB电子邮件：* user *密码：* test *用户名和密码不匹配

以下是代码：

$con = new mysqli('somewhere.com','admin','*****','nameofdb');
    if($con->connect_errno > 0){
        die('Unable to connect to database [' . $con->connect_error . ']');
    }
    else{
        echo "Successfully connected to DB ";
    }
$email = mysqli_real_escape_string($con, $_POST['eml']);
       $password = mysqli_real_escape_string($con, $_POST['pwd']);
       //$encrPassword = md5($password);


       $login = $con->query("SELECT * 
                            FROM logininfo 
                            WHERE email = $email
                            AND password = $password");
       if($login == FALSE){
            echo " email:*$email* ";
            echo " password:*$password* ";
            //echo " password:*$encrPassword* ";

            echo "Username and Password does not Match";
       }
       else {
            echo "Hey this works";
       //Check if user is logged in, if not then redirect.     
            /*session_start();
            if($_SESSION['loggedin'] == FALSE){
                $_SESSION['loggedin'] = TRUE;
                $_SESSION['username'] = $username;
            }*/
            header("Location: ../browse/index.php");
       }
        mysqli_close($con);

Answer 1

查询出错，如果你回显查询并在mysql上测试它可能更容易调试，你可以这样做：

$query = "SELECT * 
          FROM logininfo 
          WHERE email = $email
          AND password = $password";
echo $query;

祝你好运！

Answer 2

查询变量是否必须在它们周围加上引号？

SELECT * FROM sometable WHERE somecol ='$ someVar'AND someothercol ='$ someothervar';

Answer 3

两个简单的步骤 1 ..在phpmyadmin中检查你的数据库，这些用户名和密码与你输入的用户名或密码相匹配。如果是echo查询，就知道查询内部是什么。 2 ..如果你正在使用，那么确保你是否在注册时使用md5加密，然后在登录时解密它，如

$password=md5($password);

MySQL / PHP：无法从数据库中选择但元素存在

3 个答案: