(select id from owner where date_format(auction_date,'%Y-%m-%d %H:%i:00') = date_format(NOW(),'%Y-%m-%d %H:%i:00')) as a
left join (select owner_id,max(nb) as maxbid from auction group by owner_id) as b on a.id=b.owner_id
left join (select owner_id,max(mb) as maxautobid from auction group by owner_id) as c on a.id=c.owner_id
对于第二个左连接语句,我能够获得最高的mb值。有人可以帮我添加第三个左连接语句,以便我可以获得第二高的mb值吗?
答案 0 :(得分:3)
首先,您根本不需要第三次加入。您可以在一个联接中进行计算:
from (select id
from owner
where date_format(auction_date,'%Y-%m-%d %H:%i:00') = date_format(NOW(),'%Y-%m-%d %H:%i:00')
) as a left join
(select owner_id, max(nb) as maxbid, max(mb) as maxautobi
from auction
group by owner_id
) b
on a.id=b.owner_id;
获取mb
的第二大值,然后使用涉及substring_index()
和group_concat()
的技巧:
from (select id
from owner
where date_format(auction_date,'%Y-%m-%d %H:%i:00') = date_format(NOW(),'%Y-%m-%d %H:%i:00')
) as a left join
(select owner_id, max(nb) as maxbid, max(mb) as maxautobi,
substring_index(substring_index(group_concat(mb order by mb desc), ',', 2), ',', -1
) as second_mb
from auction
group by owner_id
) b
on a.id=b.owner_id;
我们的想法是将值连接在一起,按mb
排序。然后取列表的第二个元素。一个缺点是该值被转换为字符串,即使它以数字开头。