我正在尝试使用php和mysql从我的数据库中检索fata。 我已经设法从表格的第一行获取数据,但我似乎无法找到它到达第二行的方法,依此类推。
我的数据库是这样的:
(表格的第一行)
id [int] -> 7
user_id [int] -> 23
user_task_id [int] -> 4
description [varchar] -> Text Text Text Text Text
date_creation [timestamp] -> 2013-07-17
date_end [datetime] -> 0000-00-00
date_conclusion [datetime] -> 0000-00-00
status_id [int] -> 3
notes [text] -> Text Text Text Text Text Text
categoria_id [int] -> 12
entity_id [int] -> 17
(表格中的第二行)
id [int] -> 8
user_id [int] -> 6
user_task_id [int] -> 9
description [varchar] -> Text Text Text Text Text
date_creation [timestamp] -> 2013-07-20
date_end [datetime] -> 0000-00-00
date_conclusion [datetime] -> 0000-00-00
status_id [int] -> 4
notes [text] -> Text Text Text Text Text Text
categoria_id [int] -> 18
entity_id [int] -> 10
下面是代码:
<?php
function get_all_tasks() {
global $connection;
$query = "SELECT * FROM tarefas;";
$tasks_set = mysql_query($query, $connection);
confirm_query($tasks_set);
return $tasks_set;
}
?>
<table class="table_content">
<thead>
<tr>
<td>ID</td>
<td>User Task</td>
<td>Description</td>
<td>Entity ID</td>
<td>Date End</td>
<td>Status</td>
<td>Actions</td>
</tr>
</thead>
<?php
?>
<tbody>
<tr>
<?php
if($task_data = mysql_fetch_array(get_all_tasks())){
foreach ($task_data as $task) { ?>
<tr>
<td><?php echo $task['id'] ?></td>
<td><?php echo $task['user_task_id'] ?></td>
<td><?php echo $task['description'] ?></td>
<td><?php echo $task['entity_id'] ?></td>
<td><?php echo $task['date_end'] ?></td>
<td><?php echo $task['status_id'] ?></td>
<td><?php echo "" ?></td>
</tr>
<?php }}
?>
</tbody>
</table>
答案 0 :(得分:0)
尝试使用这个:
while($ task = mysql_fetch_array(get_all_tasks()){your html}
请记住,不推荐使用mysql_ *,最好使用mysqli或PDO。
答案 1 :(得分:0)
试试这个
<?php
function get_all_tasks() {
global $connection;
$query = "SELECT * FROM tarefas;";
$tasks_set = mysql_query($query, $connection);
confirm_query($tasks_set);
foreach ($task_data as $task) { ?>
<tr>
<td><?php echo $task['id'] ?></td>
<td><?php echo $task['user_task_id'] ?></td>
<td><?php echo $task['description'] ?></td>
<td><?php echo $task['entity_id'] ?></td>
<td><?php echo $task['date_end'] ?></td>
<td><?php echo $task['status_id'] ?></td>
<td><?php echo "" ?></td>
</tr>
<?php }
}
?>
<table class="table_content">
<thead>
<tr>
<td>ID</td>
<td>User Task</td>
<td>Description</td>
<td>Entity ID</td>
<td>Date End</td>
<td>Status</td>
<td>Actions</td>
</tr>
</thead>
<?php
?>
<tbody>
<tr>
<?php
echo get_all_tasks() ;
?>
</tbody>
</table>
注意:不推荐使用mysql_ *,最好使用mysqli或PDO
答案 2 :(得分:0)
将调用移到while循环之外的函数。并编写如下代码
<?php
$data = get_all_tasks();
while (($task = mysql_fetch_array($data))) {
<tr>
<td><?php echo $task['id'] ?></td>
<td><?php echo $task['user_task_id'] ?></td>
<td><?php echo $task['description'] ?></td>
<td><?php echo $task['entity_id'] ?></td>
<td><?php echo $task['date_end'] ?></td>
<td><?php echo $task['status_id'] ?></td>
<td><?php echo ""
答案 3 :(得分:0)
只需用以下内容更新您的get_all_task
功能:
<?php
function get_all_tasks() {
global $connection;
$query = "SELECT * FROM tarefas;";
$tasks_set1 = mysql_query($query, $connection);
while ($task_set = mysql_fetch_array($tasks_set1, MYSQL_ASSOC))
return $tasks_set;
}
?>