我是Java的Spring framwork的新手。并有一些问题...
我的应用程序使用spring,spring sequrity,hibernate框架
我正在写一些简单的应用程序
我有一个页面,用户可以通过hibernate添加到db
用户类:
@Entity
@Table(name="users")
public class User
{
@Id
@GeneratedValue
private Integer id;
private String login;
private String password;
@OneToOne(cascade=CascadeType.ALL)
@JoinTable(name="user_roles",
joinColumns = {@JoinColumn(name="user_id", referencedColumnName="id")},
inverseJoinColumns = {@JoinColumn(name="role_id", referencedColumnName="id")}
)
private Role role;
private Integer moneyCount;
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getLogin() {
return login;
}
public void setLogin(String login) {
this.login = login;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public Role getRole() {
return role;
}
public void setRole(Role role) {
this.role = role;
}
public Integer getMoneyCount() {
return moneyCount;
}
public void setMoneyCount(Integer moneyCount) {
this.moneyCount = moneyCount;
}
}
角色类:
@Entity
@Table(name="roles")
public class Role {
@Id
@GeneratedValue
private Integer id;
private String role;
@OneToMany(cascade=CascadeType.ALL)
@JoinTable(name="user_roles",
joinColumns = {@JoinColumn(name="role_id", referencedColumnName="id")},
inverseJoinColumns = {@JoinColumn(name="user_id", referencedColumnName="id")}
)
private Set<User> userRoles;
@Override
public int hashCode() {
return new Long(id).hashCode();
}
@Override
public boolean equals(Object obj) {
if (obj == null) {
return false;
}
if (! (obj instanceof Role)) {
return false;
}
return this.id == ((Role)obj).getId();
}
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getRole() {
return role;
}
public void setRole(String role) {
this.role = role;
}
public Set<User> getUserRoles() {
return userRoles;
}
public void setUserRoles(Set<User> userRoles) {
this.userRoles = userRoles;
}
}
保存在控制器中:
@RequestMapping(value = "/users/add", method = RequestMethod.POST)
public String addUser(@ModelAttribute("user")User user) {
user.setPassword(StatickHelpers.md5(user.getPassword()));
user.setId(15); // if remove this line i'll recive user fild id null exception
userDAO.addUser(user);
return "redirect:/users/";
}
保存在UserDAO中
@Transactional
public void addUser(User user)
{
Session session = null;
try {
session = openSession();
session.save(user);
} catch (Exception e) {
} finally {
}
}
我在页面上有一个选择块,我可以选择用户角色作为字符串 所以在保存用户时我已经
了org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.springframework.validation.BindException:
org.springframework.validation.BeanPropertyBindingResult: 1 errors
Field error in object 'user' on field 'role': rejected value [ROLE_EMPLOYER]; codes [typeMismatch.user.role,typeMismatch.role,typeMismatch.com.sprsec.model.Role,typeMismatch]; arguments [org.springframework.context.support.DefaultMessageSourceResolvable: codes [user.role,role]; arguments []; default message [role]]; default message [Failed to convert property value of type 'java.lang.String' to required type 'com.sprsec.model.Role' for property 'role'; nested exception is java.lang.IllegalStateException: Cannot convert value of type [java.lang.String] to required type [com.sprsec.model.Role] for property 'role': no matching editors or conversion strategy found]
org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:894)
org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:789)
javax.servlet.http.HttpServlet.service(HttpServlet.java:647)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:330)
据我所知,我应该在配置中创建一个bean,以帮助spring框架将convertion从string转换为Role对象? 有人可以帮我解决这个错误吗?
答案 0 :(得分:0)
尝试在BindingResult bindingResult
方法{。}}之后添加@ModelAttribute("user")User user
。
所以,你的addUser方法将是:
addUser